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3 years ago

A polynomial P has non-negative integer coefficients. If P(1) = 8 and P(10) = 2312, what is P(2)?

Mathematics

1 answer:

polet [3.4K]3 years ago

3 0

9514 1404 393

Answer:

Step-by-step explanation:

If coefficients are positive integers, then the polynomial cannot be higher degree than 3. 10^4 = 10,000, so even a coefficient of 1 will give too large a value. P(1) = 8 tells us that the sum of coefficients must be 8, so we cannot have a degree lower than 3.

The sum of digits in 2312 is 8, so it works out that the polynomial is ...

P(x) = 2x^3 +3x^2 +x +2 . . . . matches P(1) = 8 and P(10) = 2312

Then P(2) is ...

P(2) = ((2·2 +3)2 +1)2 +2

P(2) = 32

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3 years ago

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iren [92.7K]

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Step-by-step explanation:

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a = l * w

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3 years ago

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3 years ago

4) Expression: 360 What is the value?

myrzilka [38]

The value of $\sqrt{360}$ is 18.974.

Solution:

Given expression:

$\sqrt{360}$

To simplify the given expression and find the value.

$\sqrt{360}$

Factor the value 360 = 36 × 10.

$\sqrt{360}=\sqrt{36\times 10}$

36 can be written as 6 × 6 = 6²

10 can be written as 2 × 5.

$=\sqrt{6^2\times 2\times 5}$

$=6\sqrt{2\times 5}$

$=6\sqrt{10}$

= 18.974

The value of $\sqrt{360}$ is 18.974.

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4 years ago

A polynomial P has non-negative integer coefficients. If P(1) = 8 and P(10) = 2312, what is P(2)?​

A polynomial P has non-negative integer coefficients. If P(1) = 8 and P(10) = 2312, what is P(2)?