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larisa [96]
3 years ago
15

Find The range and interquartile 45279.11, 5271. 04, 5309.73, 5363.38, 5409.72, 5444.74,  5603.46, 5695.39, 5871.96, 5972.35


Mathematics
1 answer:
dangina [55]3 years ago
8 0

Answer:

40008 07 is the answer good luck :)

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The area of a room is 26.025 m sqaure. If its length is 12.5m . find the breadth of the room​
ddd [48]

Answer:

2.082.

Step-by-step explanation:

Solution,

Given,

Area ( A ) = 26.025 m².

Length ( L ) = 12.5 m.

Now,

Breadth ( B ) = Area ÷ Length.

= 26.025 ÷ 12.5

= 2.082.

Thus, The breadth of the room is 2.082 m.

3 0
3 years ago
cuanto dinero se debe invertir a un interes de 14% compuesto continuamente para tener $500,000 en 35 años?
Alja [10]

Answer:

Se necesita depositar un capital inicial de $ 5096.83 pesos para lograr $ 500000 pesos a un interés compuesto de 14 % anual luego de 35 años.

Step-by-step explanation:

La cantidad ahorrada bajo interés compuesto está definida por la siguiente fórmula:

C(t) = C_{o}\cdot (1+r)^{t} (1)

Donde:

C_{o} - Capital inicial, medido en pesos.

C(t) - Capital actual, medido en pesos.

r - Tasa de interés, sin unidad.

t - Anualidad, medida en años.

Asumiendo que la tasa de interés compuesto es anual y si C(t) = 500000, r = 0.14 y t = 35, entonces el capital inicial es:

C_{o} = \frac{C(t)}{(1+r)^{t}}

C_{o} = \frac{500000}{(1+0.14)^{35}}

C_{o} = 5096.83

Se necesita depositar un capital inicial de $ 5096.83 pesos para lograr $ 500000 pesos a un interés compuesto de 14 % anual luego de 35 años.

6 0
3 years ago
The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same
masha68 [24]

Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

Step-by-step explanation:

Let x and y area the random variable that represents the heights of women and men.

Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.

i.e. \mu_1 = 64   \sigma_1=2.7

Since , z=\dfrac{x-\mu}{\sigma}

Then, z-score corresponds to  a woman 6 feet tall (i.e. x=72 inches).

[∵  1 foot = 12 inches , 6 feet = 6(12)=72 inches]

z=\dfrac{72-64}{2.7}=2.96296296\approx2.96

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.

i.e. \mu_2 = 69.3   \sigma_2=2.8

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).

[∵  1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

z=\dfrac{70-69.3}{2.8}=0.25

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

6 0
3 years ago
Find the exact value of sec (–660)°
Nostrana [21]
Add full rotations of 360° degree until the angle of between 0° and 360°.
Sec (60)
The exact value is sec (60) is 2
8 0
3 years ago
Use the rule for order of operations to simplify the expression as much as possible 67−4(3⋅8−10)=
PilotLPTM [1.2K]

67-4\cdot(3\cdot8-10)=67-4\cdot(24-10)=\\\\=67-4\cdot14=67-56=\boxed{11}

6 0
3 years ago
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