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Light bulbs manufactured at a certain factory have a 3% probability of being defective. what is the probability that 5 out of a

lbvjy [14]

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. The probability that 5 out of a shipment of 30 will be defective is 0.001617.

<h3>What is Binomial distribution?</h3>

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. It is given by the formula,

P(x) = ⁿCₓ pˣ q⁽ⁿ⁻ˣ⁾

Where,

x is the number of successes needed,

n is the number of trials or sample size,

p is the probability of a single success, and

q is the probability of a single failure.

The probability of the bulb being defective is 3%(0.03) and the probability of the bulb not being defective is 97%(0.97).

Now, it is needed to be found that the probability that 5 out of a shipment of 30 will be defective can be written as,

P(x) = ⁿCₓ pˣ q⁽ⁿ⁻ˣ⁾

P(x=5) = ³⁰C₅ (0.03)⁵ (0.97)²⁵

P(x=5) = 0.001617

Hence, the probability that 5 out of a shipment of 30 will be defective is 0.001617.

Learn more about Binomial Distribution:

brainly.com/question/14565246

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3 0

2 years ago

Please helppp!!! 1-20 thank u!!!!!

AVprozaik [17]

Answer:

Step-by-step explanation:

1. 249-142=107

2. Can't see the other number.

3. Hard to tell.

4. 27,975.215*100=2,797,521.5‬

5. 42.19 divided by 100 = 0.4219‬

6. I have no clue.

7. 204 divided by 12 = 17. So, K is 17.

8. Don't know.

9. Don't know

10. a 39.72. b Don't know.

11. a one hundred fourteen and six hundred seventy-four thousandths

b two million six hundred nine thousand two hundred fifty-two and sixty-four thousand eighty-one hundred-thousandths

12. Don't know.

13. 8.85 * 80.3 = 710.655‬

14. 0.04855‬ divided by 0.971 = 0.05

15. 0.147696‬ divided by 0.724‬ = 0.204‬

16. 831.5‬ - 47.79‬ = 783.71‬

17. 9.411‬ + 0.455 = 9.866‬

18. 558.24 - 541.6 = 16.64‬. So, E would be 16.64.

19. 6.84 * 0.52 = 7.36‬

20. 28 * 0.37 = 10.36‬

Hope this helps! This took me a while.

7 0

4 years ago

A club can select one member to attend a conference. All of the club officers want to attend. There are a total of four officer

Shtirlitz [24]

Answer:

0.25

Step-by-step explanation:

Given that a club can select one member to attend a conference. All of the club officers want to attend. There are a total of four officers, and their designated positions within the club are President (P), Vice dash President (Upper V )comma Secretary (Upper S )comma nbspand Treasurer (Upper T ).

Sample space would be

a){ {P}, {V}, {S} {T}} is the sample space with notations standing for as given in the question

b) Each sample is equally likely. Hence we have equal chances for selecting any one out of the four.

If probability of selecting a particular sample of size I is p, the by total probability axiom we have

$4p =1\\p =0.25$

8 0

3 years ago

A shop sells one-pound bags of peanuts for $2 and three-pound bags of peanuts for $5. If 9 bags are purchased for a total cost o

Lemur [1.5K]

Answer:

D. 6

Step-by-step explanation:

One-pound bags sell for $2

Three-pound bags sell for $5

9 bags were sold for $36

6*$5=$30 (three pound bags)

3*$2=$6 (one pound bags)

$30+$6=$36

So 6 of the three-pound bags were sold

6 0

3 years ago

Anja collected data about the number of dogs 9th-grade students own. She created this histogram to represent the data and determ

sattari [20]

D) <span>She is correct; the histogram is skewed to the right because there is less data on the right side.</span>

6 0

3 years ago

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