Explanation:
f(x) = (x-4)(x+2)
1) For x-intercept, y will be 0
<u />
<u>x-intercept</u>: (4, 0), (-2, 0)
2) For vertex: x = -b/2a where ax² + bx + c
<u>Quadratic function</u>:
<u>vertex</u>:
y: (x-4)(x+2) = (1-4)(1+2) = -9
ordered pair of vertex: (1, -9)
3) For y-intercept, x will be 0
<u>y-intercept</u>: (0, -8)
Answer:
2
Step-by-step explanation:
<u>Answer</u>
2nd diagram
<u>Explanation.</u>
When contraction a parallel line from a point say N, outside the line, the first thing is to draw a line from point N to the that line.
The point where this line from N intersect with line, name it say P. From this point you can use the properties of angles in a parallel lines to construct the parallel line.
The line NP can act like a transverse of the two parallel lines. The diagram 2 shows first step.
Answer:
See below ~
Step-by-step explanation:
The given polynomial : <u>-2x + 1 + 2x²</u> needs to be written in the form :
- ax² + bx+c
- a is the coefficient of x²
- b is the coefficient of x
- c is the constant term
On rewriting in this asked format,
- 2x² - 2x + 1
- a = 2
- b = -2
- c = 1