Answer:
2/10
Step-by-step explanation:
Probability of getting head on i'th coin = i/10
Probability Pr of getting head on 2nd coin (Event A) = 2 / 10
Probability Pr of getting head on 1st coin (Event B) = 1/10
Probability A given B = Pr (A/B) = Pr (A∩B) / Pr B ;
where A∩B = Pr (A & B) = Pr A X Pr B
Putting in above formula :
Pr (A/B) = <u>[(</u>1/10)x(2/10<u>)]</u> / 1/10
= 2/10
Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125
Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50. #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5
The sum of all three is 6x^2y + 2xy^2
The answer is 7/5. I attached the work below.
