Answer:
7.46 J/kg/K
Explanation:
The heat absorbed or lost is:
q = mCΔT
where m is the mass, C is the heat capacity, and ΔT is the change in temperature.
Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:
15.0 J = (0.201 kg) C (10.0 °C)
C = 7.46 J/kg/°C
Which is the same as 7.46 J/kg/K.
Given
m1 = 15kg
vi1 = +20 m/s
vf1 = +5 m/s
m2 = 10 kg
vi2= -15 m/s
vf2 = ?
Procedure
Conservation of momentum, general law of physics according to which the quantity called momentum that characterizes motion never changes in an isolated collection of objects; that is, the total momentum of a system remains constant.

The speed of the 10kg Ball is 7.5m/s
Answer:
Correct answer: a = 15.46 m/s²
Explanation:
The formula for accelerated movement with the given data is:
V² - V₀² = 2 · a · d where the initial velocity V₀ and the final V
Since the initial velocity V₀ is zero, the formula is:
V² = 2 · a · d => a = V² / (2 · d) = 27.8² / (2 · 25) = 772.84 / 50 = 15.46 m/s²
a = 15.46 m/s²
God is with you!!!
Q=l^2 times R times t
Where Q - heat, I -current, R - resistance and t is time
If you increase I twice (and it's squared), than Q gonna went up 4 times (2 squared).
Choose last
Bert would be going 34mph due to the taill winds being 6mph