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ollegr [7]
3 years ago
15

When I rub my hands together they feel warm. I am converting____

Physics
1 answer:
Elena L [17]3 years ago
4 0

Answer:

thermal

Explanation:

sorry if you get it wrong

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Based on Dalton’s law of partial pressures if I have 1 L sample of helium at standard temperature has pressure has a volume of 2
sammy [17]

Answer:

wat?.... anyways if 2 + 2 is 4 then what is 10 x 3974793 ?

Explanation:

8 0
2 years ago
An open system starts with 52 J of mechanical energy. The energy changes
MArishka [77]

Answer:

ITS C 47

Explanation:

5 0
4 years ago
Read 2 more answers
Write the nuclear reaction equation for the beta decay of Iodine-131
den301095 [7]

Answer:

_{53}^{131}I \rightarrow _{54}^{131}Xe + e + \bar{\nu}

Explanation:

In a beta (minus) decay, a neutron in a nucleus turns into a proton, emitting a fast-moving electron (called beta particle) alongside with an antineutrino.

The general equation for a beta decay is:

^A_Z X \rightarrow _{Z+1}^AY+^0_{-1}e+ ^0_0\bar{\nu} (1)

where

X is the original nucleus

Y is the daughter nucleus

e is the electron

\bar{\nu} is the antineutrino

We observe that:

  • The mass number (A), which is the sum of protons and neutrons in the nucleus, remains the same in the decay
  • The atomic number (Z), which is the number of protons in the nucleus, increases by 1 unit

In this problem, the original nucles that we are considering is iodine-131, which is

_{53}^{131}I

where

Z = 53 (atomic number of iodine)

A = 131 (mass number)

Using the rule for the general equation (1), the dauther nucleus must have same mass number (131) and atomic number increased by 1 (54, which corresponds to Xenon, Xe), therefore the equation will be:

_{53}^{131}I \rightarrow _{54}^{131}Xe + e + \bar{\nu}

7 0
3 years ago
Read 2 more answers
A high-speed railway car goes around a flat, horizontal circle of radius 480 m at a constant speed. The magnitudes of the horizo
kvv77 [185]

Answer:

Net force ( F ) = 208 N.

Speed of car ( v ) = 68.58 m/s.

Explanation:-

The radius ( r ) = 480 m.

Mass of passenger ( m ) = 65 kg.

Horizontal force ( f_{x} ) = 208 N.

Vertical force ( f_{n} ) = 637 N.

Net vertical component of force ( f_{x} ) = m*g - 637   = 65 * 9.8 - 637 =  0 N.

a ) magnitude of net force .

F = \sqrt{f^{2} _{x} + f^{2} _{y}  }   = \sqrt{208^{2} + 0^{2} }   = 208 N.

b) The speed of car.

f_{n}  = \frac{m*v^{2} }{r}    where v is the velocity.

637 = \frac{65 *v^{2} }{480}

v² = 4704

v = 68.58 m/s.

6 0
3 years ago
A student drops an object from a fourth floor window the velocity of the objects is measured at 39.28m/s 3 seconds later what is
quester [9]

Answer:

Acceleration due to gravity 9.8 m/s^2

Explanation:

When an object drops down towards earth from certain height than it comes down with an acceleration of 9.8 m/s^2 which is constant throughout the dropping until the falling objects hits the ground and coming to rest.

7 0
3 years ago
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