F = 52000 N
m = 1060 kg
a= F/m = 52000 N/1060 kg = 49.0566 m/s^2
The cart travelled a distance of 14.4 m
Explanation:
The work done by a force when pushing an object is given by:
![W=Fd cos \theta](https://tex.z-dn.net/?f=W%3DFd%20cos%20%5Ctheta)
where:
F is the magnitude of the force
d is the displacement
is the angle between the direction of the force and the displacement
In this problem we have:
W = 157 J is the work done on the cart
F = 10.9 N is the magnitude of the force
, assuming the force is applied parallel to the motion of the cart
Therefore we can solve for d to find the distance travelled by the cart:
![d=\frac{W}{F cos \theta}=\frac{157}{(10.9)(cos 0)}=14.4 m](https://tex.z-dn.net/?f=d%3D%5Cfrac%7BW%7D%7BF%20cos%20%5Ctheta%7D%3D%5Cfrac%7B157%7D%7B%2810.9%29%28cos%200%29%7D%3D14.4%20m)
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
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Answer:
it is sooo easy u need to use magnetic panels on the rail and put the magnet on the train it works under the principal of magnetic
Answer:
Given: V = 220V, Pmin = 360W, Pmax = 840W
For minimum heating case:
We know that
Pmin = VI
360 = 220 X I
I = 1.63 amp
R = V/I
R = 220/1.63
R = 134.96ohms
For maximum heating case:
We know that
Pmax = VI
840 = 220 X I
I = 3.81 amp
R = V/I
R = 220/3.81
R = 57.74 ohms
Answer:
t = 0.28 seconds
Explanation:
Given that,
Force acting on a firework, F = 700 N
The momentum of the firework, p =200 kg-m/s
We need to find the time before it explodes. Ket the time be t. We know that, the rate of change of momentum is equal to external frce. So,
![F=\dfrac{P}{t}\\\\t=\dfrac{P}{F}\\\\t=\dfrac{200}{700}\\t=0.28\ s](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7BP%7D%7Bt%7D%5C%5C%5C%5Ct%3D%5Cdfrac%7BP%7D%7BF%7D%5C%5C%5C%5Ct%3D%5Cdfrac%7B200%7D%7B700%7D%5C%5Ct%3D0.28%5C%20s)
So, the required time is equal to 0.28 seconds.