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dusya [7]
4 years ago
10

The battery charger for an mp3 player contains a step-down transformer with a turns ratio of 1:38, so that the voltage of 120 v

available at a wall socket can be used to charge the battery pack or operate the player. what voltage does the secondary coil of the transformer provide?
Physics
1 answer:
matrenka [14]4 years ago
7 0
Transformer contains two coils: primary and secondary. They allow change of voltage to lower or higher value. In first case we have step-down and in second case we have step-up transformer.
Formula used for transformer is:\frac{N_{1} }{N_{2}} = \frac{V_{1}}{V_{2}}

Where:N1 = number of turns on primary coilN2 = number of turns on secondary coilV1 = voltage on primary coilV2 = voltage on secondary coil
In a step-down transformer primary coil has more turns than secondary coil. So the ratio 1:38 means that for each turn on secondary coil we have 38 turns on primary coil.
We can solve the equation for V2:V_{2} =  \frac{ V_{1}* N_{2}  }{ N_{1} }  \\  V_{2} =  \frac{ 120* x  }{ 38x} } \\ V_{2} = 3.16V

Secondary coil provides voltage of 3.16V.
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Change the following back to a standard number... (3.15 x 10-3)
Grace [21]
You mean simplify it? I don’t see how this is a physics question.
5 0
3 years ago
Estimate the kinetic energy of the earth with respect to the sun as the sum of two terms.
nekit [7.7K]

The definition of kinetic energy allows to find the result for the relationship between the energy of the sun and the Earth is:

  • The kinetic energy ratio is   \frac{K_{Sum} }{K_{Earth}} = 5.3 \ 10^2
<h3 /><h3 /><h3> Kinetic enrgy.</h3>

Kinetic energy is the energy due to the movement of bodies, it is given by the relation

          K = ½ m v²

where K is the kinetic energy, m the mass of the body and v the velocity of the body.

In a compound motion it is common to separate energy into parts to simplify calculations.

  • Translational kinetic energy. Due to the linear movement of the body

            K_{tras} =\frac{1}{2} m v^2

  • Rotational kinetic energy. Due to the rotational movement of the body.

            K_{rot} = \frac{1}{2} I w^2

Where I is the inrtia momentum and w the angular velocity.

They indicate that we compare the kinetic energy of the sun and the Earth.

The Earth has two movements, one of rotation about its axis with a period of T = 24 h and one of translation with respect to the Sun with a period of T= 365 days, therefore the kinetic energy of the Earth.

           K_{earth} = K_{tras} + K_{rot}

Linear and rotational speed are related.

           v = w r

The Earth is an almost spherical body therefore the moment of inertia of a solid sphere.

           I = \frac{2}{5 }  m r^2  

Let's  subatitute.

         

          K_{earth} = \frac{1}{2} \  m r^2_{tras} w^2_{tras} + \frac{1}{2} ( \frac{2}{5} m r^2_{earth}) w^2_{rot}  

The movement of the Earth around the sun is almost circular, therefore we can use the relations of the uniform circular movement, where the angle for one revolution is 2π radians and the time is called the period.

       w = \frac{2 \pi}{T}  

Let's substitute.

        K_{earth} = \frac{1}{2} m ( \frac{2\pi r^2_{tras}}{T_{tras}})^2  \ + \frac{1}{5} m (\frac{2\pi r^2_{earth} }{T^2_{rot}})^2  

        K_{earth} = 4 \pi^2 \ m \ ( \frac{1}{2} [ \frac{r_{tras}}{T_{tras}y} ]^2 + \frac{1}{5} [ \frac{r_{rot}}{T_{rot}}]^2)  

Data for Earth are tabulated:

  • Mass m = 5.98 1024 kg
  • Radius r = 6.37 10⁶ m
  • Radius orbits tras = 1.496 10¹¹ m
  • Rotation period T_{rot} = 24 h (\frac{3600s}{1h}) = 8.64 10⁴s
  • Translation period  T_{tras} = 365 d (\frac{24h}{1 d}) (\frac{3600s}{1h}) = 3.15 10⁷ s

Let's calculate.

        K_{earth} = 4 \pi^2 5.98 \ 10^{24}  ( \frac{1}{2} ( \frac{1.496 \ 10^{11}}{3.15 \ 10^7 } )^2  \ +  \frac{1}{5}( \frac{6.37 \ 10^6 }{8.64 \ 10^4})^2 )

        K_{earth} = 2.36 \ 10^{26 } \ (1.128 \ 10^7 + 1.087 \ 10^3)

        K_{earth}= 2.66 \ 10^{33} J

Let's analyze the kinetic energy for the Sun, this is inside the solar system therefore it has no translation movement and is approximately a sphere with a rotation period of T_{Sum} = 27 days.

The kinetic energy of the sun is;

          K_{sum} = K_{rot} =  \frac{1}{2} I w^2  

          K_{sum} = \frac{1}{2} (\frac{2}{5} M R^2) (\frac{2\pi}{T_{sum}})^2  

          K_{sum} = \frac{4\pi^2 }{5} M (\frac{R}{T_{rot}})^2  

The tabulated data for the sun are:

  • Mass m = 1,991 1030 kg.
  • Radius R = 6.96 10⁸ m
  • Period T = 27 d (\frac{24h}{1 d} ) (\frac{3600s}{1h}) = 2.33 10⁶ s

         

Let's calculate.

           

          K_{sum} = 1.40 \ 10^{36} J

The relationship of the kinetic energy of the sun and the Earth is:

        \frac{K_{sum}}{K_{earth}} = \frac{1.40 \ 10^{36}}{2.66 \ 10^{33}}  

       \frac{K_{sum}}{K_{earth}} =  5.3 \ 10^2  

In conclusion using the definition of kinetic energy we can shorten the result for the relationship between the energy of the sun and the Earth is:

  • The kinetic energy ratio is:  \frac{K_{Sum}}{K_{Earth}} = 5 \ 10^2

Learn more about kinetic energy here: brainly.com/question/25959744

5 0
3 years ago
Particles of m1 and m2 (m2&gt;m1) are connected by a line in extensible string passing over a smooth fixed pulley. Initially, bo
Tresset [83]

Answer:

The velocity with which the mass will hit the floor is v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.}

Explanation:

If the tension in the string is T, for m_1 we have

T- m_1g =m_1a,

and for the mass m_2

T -m_2g = -m_2a

From these equations we solve for a and get:

a =(\dfrac{m_2-m_1}{m_2+m_1}) g.

The kinematic equation

v_f^2 = v_0^2+2ax

gives the final velocity v_f of a particle, when its initial velocity was v_0, and has traveled a distance x while undergoing acceleration a.

In our case

v_0 = 0 (the initial velocity of the particles is zero)

a =(\dfrac{m_2-m_1}{m_2+m_1}) g.

which gives us

v_f^2 = 2ax

v_f^2 =2(\dfrac{m_2-m_1}{m_2+m_1}) g

\boxed{v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.} }

which is the velocity with which the mass m_2 will hit the floor.

8 0
3 years ago
On his way to class, a student on a skateboard is accelerating on a downhill stretch. Which of the following statements is true?
sasho [114]

Answer:

B is correct

Explanation:

Because of gravity

3 0
4 years ago
An empty capacitor is capable of storing 1.0 × 10-4 J of energy when connected to a certain battery. If the distance between the
dangina [55]

Answer:

Explanation:

Energy stored in a capacitor

= 1/2 C₁V²

capacity of a capacitor

c = εK A / d

k is dielectric and d is distance between plates .

When  the distance between the plates is halved and then filled with a dielectric (κ = 4.3)

capacity becomes 4.3  x 2 times

New capacity

C₂ = 8.6 C₁

Energy of modified capacitor

1/2 C₂ V²= 1/2 x 8.6 c x V²

Energy becomes

8.6 times.

Energy stored = 8.6 x 10⁻⁴ J

3 0
4 years ago
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