Remember
(ab)/(cd)=(a/c)(b/d)
and
1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=
=
=
a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
</span>
Answer:
A. Minimum = 54, Q1= 69.5, Median = 75, Q3= 106, Maximum = 183
Step-by-step explanation:
Arranging the data set in order from least to greastest we get:
54, 68, 71, 72, 75, 84, 104, 108, 183
From this, we can see that the minimum value is 54 and the maximum value is 183.
Taking a number off one by one on each side of the data set gives the median. In the middle lies 75, so that is our median
To find quartile ranges, split the data set into two where the median lies, then, find the median of those two data sets. The medians will be the values of the upper (Q3) and lower quartiles (Q1).
Q1: 54, 68, 71, 72
68 + 71 = 139
139 ÷ 2 = 69.5
-----
Q3: 84, 104, 108, 183
104 + 108 = 212
212 ÷ 2 = 106
Option A is the only answer with all of these values, therefore, it is the answer.
hope this helps!
It does not look like Suro even made an error. She took the square root of both sides to get x = 7, I don't see any problem here.
Answer:
This statement is false
Step-by-step explanation:
5 is less than 12 so it should be written like this
5 < 12
Alligator mouth faces the larger numbers
