Using the Hardy-Weinberg equations, the percentage of carriers of cystic fibrosis is 8.19%.
<h3>What are the Hardy-Weinberg equations?</h3>
The Hardy-Weinberg equations describe the relationship between alleles in a population that is fairly constant.
The Hardy-Weinberg equations are given below as;
Hardy-Weinberg equations
Percentage of carriers = 2pq
Percentage of carriers = 2 * 0.09 * 0.91 * 100 = 8.19%
Therefore, the percentage of carriers of cystic fibrosis is 8.19%.
Learn more about Hardy-Weinberg equations at: brainly.com/question/16039271
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A. Average weather conditions over extended periods of time
Taskmasters. Land breezes occur at night and in the early morning.This winds occur when the land is cooler than the sea. This happens when the air cools in the night time (as there is less heating from the sun) it contracts
Here's what we know:
10,000 individuals
6,840 individuals have blood type AA
2,860 individuals have blood type AB
300 individuals have blood type BB
AA genotype frequency: 68.4%
AB genotype frequency: 28.6%
BB genotype frequency: 3%
The A allele occurs 6,840 * 2 + 2,860 * 1 = <span>16,540 times, which is a frequency of 82.7%, meaning the B allele occurs 3,460 times, which is a frequency of 17.3%. In the next generation, 3%, or 750, individuals would have blood type BB.</span>
