1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
levacccp [35]
3 years ago
10

Find the length of side AB Give answer to 3 significant figures

Mathematics
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

AB = 8.857 cm

Step-by-step explanation:

Here, we are given a <em>right angle</em> \triangle ABC in which we have the following things:

\angle A = 90 ^\circ\\\angle C = 41 ^\circ\\\text{Side }BC = 13.5 cm

Side <em>BC </em>is the hypotenuse here.

We have to find the side <em>AB</em>.

Trigonometric functions can be helpful to find the value of Side AB here.

Calculating \angle B:

Sum of all the angles in \triangle ABC is 180^\circ.

\Rightarrow \angle A + \angle B + \angle C = 180^\circ\\\Rightarrow 90^\circ + \angle B + 41^\circ = 180^\circ\\\Rightarrow \angle B = 49^\circ

We know that <em>cosine </em>of an angle is:

cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}\\\Rightarrow cos B = \dfrac{AB}{BC}\\\Rightarrow cos 49^\circ = \dfrac{AB}{13.5}\\\Rightarrow AB = 13.5 \times 0.656\\\Rightarrow AB = 8.857 cm

So, side AB = 8.857 cm .

You might be interested in
What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x4+5 ?
Valentin [98]
Attached a solution and showed work.

8 0
3 years ago
A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp
abruzzese [7]

Step-by-step explanation:

<em>"A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp."</em>

<em />

<em>"(a) During a morning activity of the camp, these 12 players have to randomly group into six pairs of two players each."</em>

<em>"(i) Find the total number of possible ways that these six pairs can be formed."</em>

The order doesn't matter (AB is the same as BA), so use combinations.

For the first pair, there are ₁₂C₂ ways to choose 2 people from 12.

For the second pair, there are ₁₀C₂ ways to choose 2 people from 10.

So on and so forth.  The total number of combinations is:

₁₂C₂ × ₁₀C₂ × ₈C₂ × ₆C₂ × ₄C₂ × ₂C₂

= 66 × 45 × 28 × 15 × 6 × 1

= 7,484,400

<em>"(ii) Find the probability that each pair contains players of the same gender only. Correct your final answer to 4 decimal places."</em>

We need to find the number of ways that 6 boys can be grouped into 3 pairs.  Using the same logic as before:

₆C₂ × ₄C₂ × ₂C₂

= 15 × 6 × 1

= 90

There are 90 ways that 6 boys can be grouped into 3 pairs, which means there's also 90 ways that 6 girls can be grouped into 3 pairs.  So the probability is:

90 × 90 / 7,484,400

= 1 / 924

≈ 0.0011

<em>"(b) During an afternoon activity of the camp, 6 players are randomly selected and 6 one-on-one matches with the coach are to be scheduled.</em>

<em>(i) How many different schedules are possible?"</em>

There are ₁₂C₆ ways that 6 players can be selected from 12.  From there, each possible schedule has a different order of players, so we need to use permutations.

There are 6 options for the first match.  After that, there are 5 options for the second match.  Then 4 options for the third match.  So on and so forth.  So the number of permutations is 6!.

The total number of possible schedules is:

₁₂C₆ × 6!

= 924 × 720

= 665,280

<em>"(ii) Find the probability that the number of selected male players is higher than that of female players given that at most 4 females were selected. Correct your final answer to 4 decimal places."</em>

If at most 4 girls are selected, that means there's either 0, 1, 2, 3, or 4 girls.

If 0 girls are selected, the number of combinations is:

₆C₆ × ₆C₀ = 1 × 1 = 1

If 1 girl is selected, the number of combinations is:

₆C₅ × ₆C₁ = 6 × 6 = 36

If 2 girls are selected, the number of combinations is:

₆C₄ × ₆C₂ = 15 × 15 = 225

If 3 girls are selected, the number of combinations is:

₆C₃ × ₆C₃ = 20 × 20 = 400

If 4 girls are selected, the number of combinations is:

₆C₂ × ₆C₄ = 15 × 15 = 225

The probability that there are more boys than girls is:

(1 + 36 + 225) / (1 + 36 + 225 + 400 + 225)

= 262 / 887

≈ 0.2954

7 0
3 years ago
A number line is drawn left to right with integers spaced 1 centimeter apart. An ant crawls onto the number line at +3. It then
Anna11 [10]

Answer:

-1.2 cm

Step-by-step explanation:

Let's figure out where the ant is after each step.

Step 1

Start at      +3.0

Move left  <u> - 1.5 </u>

Now at       +1.5

Step  2

Start at           +1.5

Move right  <u> + 4.9 </u>

Now at         +6.4

Step 3

Start at      +6.4

Move left <u> - 7.6 </u>

Now at      -1.2

The ant is now at -1.2 cm.

6 0
3 years ago
Whats 125% as a fraction and a decimal
ZanzabumX [31]
125% as a fraction is 1 25/100 and in decimal form it is 1.25.
5 0
3 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️PLEASE PLEASE HELP I HAVE BEEN WAITING FOR OVER AN HOUR
Gnoma [55]
I cant see the screen clearly
6 0
3 years ago
Other questions:
  • 450 miles on 15 gallons of gas is what in a rate?
    7·1 answer
  • Given the median QR and trapezoid MOPN, what is the value of x?
    14·2 answers
  • Choose the digit that shows 3.096 rounded to the nearest hundred
    5·2 answers
  • Round 3586 to the nearest 10
    14·1 answer
  • Guys..please I really need you guys to help me please cause my hw will submit tomorrow
    15·1 answer
  • HELP PLZZZS!!!!!!! EASY 10 points *easy*
    14·2 answers
  • Use the diagram below to determine the height of the flagpole
    5·1 answer
  • How i can answer this question, NO LINKS, if you answer correctly i will give u brainliest!
    5·1 answer
  • An equation is shown<br> X + 1 = 9x - 3<br> What is the solution?
    5·1 answer
  • Write down the indicated trigonometric value and write as decimal and round to thousandths place
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!