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svetlana [45]
3 years ago
10

a store had 2 blue chairs for $22.78 or 6 red chairs $67.80 which color chair has a lower unit price?

Mathematics
1 answer:
ANEK [815]3 years ago
6 0

Answer:

Red

Step-by-step explanation:

total cost of blue divided by number of blue (22.78/2) is greater than total cost of red divided by number of red (67.80/6).

Blue unit cost: 11.39

Red unit cost: 11.30

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Sunny_sXe [5.5K]
The answer here would be <span>ON/C 6 8 – 5 – 6 2 . 5 0 + 7 5 =</span>
4 0
3 years ago
-20 - 4y when y = -3 need help asap
andreev551 [17]
Since y=-3 you need to set up the equation
-20-(-3)
And all you have to do is simplify
So your answer will be
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Hope this helped :)
Have a great day
8 0
3 years ago
ou have space in your garden for 60 small flowering bulbs. Crocus bulbs cost $0.45 each and daffodil bulbs cost $0.65 each. Your
bogdanovich [222]

9514 1404 393

Answer:

  • 20 crocus
  • 40 daffodil

Step-by-step explanation:

Let d represent the number of daffodil bulbs you buy. Then 60-d is the number of crocus bulbs. The total cost will be ...

  0.45(60 -d) +0.65(d) = 35.00

  27 +0.20d = 35

  0.20d = 8 . . . . . . . . . subtract 27

  d = 40 . . . . . . . . . . multiply by 5

  60 -40 = 20 . . . . . crocus bulbs

You can buy 20 crocus bulbs and 40 daffodil bulbs for $35.

7 0
3 years ago
There is a 4-foot fence that surrounds your backyard. The fence casts a shadow that is 5 feet long. If you are 6 feet tall and s
Strike441 [17]
My shadow would be 7 feet tall.

Since I am standing next to the fence, then whatever difference its actual height and its shadow has, will be the same difference of my shadow to my actual height.

fence: Actual height - 4 ft ; Shadow height - 5 ft; difference - 1 ft
me    : Actual height - 6 ft : Shadow height - ?   ; difference - 1ft

Shadow Height - Actual Height = 1 ft
Sh - 6ft = 1ft
Sh = 1ft + 6ft
Sh = 7ft
3 0
3 years ago
What is the solution to log (10x-1)= logs(9x+ 7)?
Xelga [282]

Answer:

x=8

Step-by-step explanation:

\log _{10}\left(10x-1\right)=\log _{10}\left(9x+7\right)\\\mathrm{Apply\:log\:rule:\:\:If}\:\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\:\mathrm{then}\:f\left(x\right)=g\left(x\right)\\10x-1=9x+7\\\mathrm{Add\:}1\mathrm{\:to\:both\:sides}\\10x-1+1=9x+7+1\\\mathrm{Subtract\:}9x\mathrm{\:from\:both\:sides}\\10x-9x=9x+8-9x\\\mathrm{Simplify}\\x=8\\

5 0
3 years ago
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