The equations y = x² - 2x + 1 and 2x - y = 2 intersect at the points (1, 0) and (3, 4)
<h3>What is an equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Given that the quadratic function intersecting a linear function at points (1, 0) and (3, 4)
This means that this points lie on both functions.
y = x² - 2x + 1 and 2x - y = 2
For point (1, 0):
y = 1² - 2(1) + 1 = 0; 2(1) - 0 = 2
For point (3, 4):
y = 3² - 2(3) + 1 = 4; 2(3) - 4 = 2
The equations y = x² - 2x + 1 and 2x - y = 2 intersect at the points (1, 0) and (3, 4)
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If AB = CD, then 3x+4 is equal to 4x-1
3x + 4 = 4x - 1
Add one to both sides to cancel out.
3x + 5 = 4x
Subtract 3x from both sides to cancel out.
5 = x
Now, substitute the 5 in place of the x in the equation for AB (3x+4)
3(5) + 4
15 + 4
19
Final Answer: B) 19
Answer:
me please
Step-by-step explanation:
Step-by-step explanation:
this should be correct but im not 100%sure