Let s represent the short side of the triangle. The long sides of the triangle are each s+1, and the triangle's perimeter is
... s + (s+1) + (s+1) = 3s+2
The length of one side of the square is s-2, and its perimeter is 4 times that, 4(s-2) = 4s-8. The square and triangle have the same perimeter, so
... 3s+2 = 4s-8
... 10 = s . . . . . . . . add 8-3s to both sides
The length of the shorter side of the triange is 10 units.
Remainder of 6099 Divided by 7? The quotient (integer division) of 6099/7 equals 871; the remainder (“left over”) is 2.
Answer:
B. Step 2 uses the associative property, and step 3 uses the commutative property.
Step-by-step explanation:
The associative property lets you group terms for addition any way you like. It appears that in Step 2, the grouping is ...
4 + (1/6 + 3) + 5/6
The commutative property lets you change the order of any pair of terms involved in addition. It appears that in Step 3, the order of the terms within the group has been swapped.
4 + (3 + 1/6) + 5/6
_____
<em>Comment on associative and commutative properties</em>
What applies to terms in addition applies to factors in multiplication.
P(1) = P(-1)
P(1) = 3 - a + b
P(-1) = -3 + a + b
-> 3 - a + b = -3 + a + b
-> 3 - a + b + 3 - a - b = 0
-> 6 - 2a = 0
-> a = 3.
P(2) = 24 - 2a + b -> 24 - (2a - b) = 16 -> 2a - b = 8
-> 6 - b = 8
b = -2.
So, a = 3 and b = -2
Recheck : P(1) = 3 - 3 + (-2) = -2
P(-1) = -3 + 3 + (-2) = -2 => P(1) = P(-1) (true)
P(2) = 24 - 6 + (-2) = 16.
Answer:
search it up
Step-by-step explanation:
