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Anna35 [415]
3 years ago
13

Hi please help im honestly so tired and I don't have the time to constantly read this so I can get it

Mathematics
2 answers:
rodikova [14]3 years ago
8 0

ANSWER: 3

<em><u>image at the bottom to help you visualize!</u></em>

First, Let's graph point A:

( The red point )

Now reflect point a across the X axis which is the horizontal line (to get point B):

( The blue point )

We see that --> in the point (5,-3), the y coordinate, (-3) changed to (3)

SO THE ANSWER WOULD BE:<u> 3</u>

Summary:

When you reflect a point across the x-axis, the x-coordinate remains the same, but the y-coordinate is transformed into its opposite (its sign is changed).

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).

HOPE THIS HELPS!

shutvik [7]3 years ago
4 0
When your doing a reflection over the X axis you want to switch the X cordinate that you are give to the opposite of +/- like if (-5,3) and your flipping it over the X axis it would be (5,3) but in this case your flipping it over the Y axis and you need to switch the Y cordinate to the opposite number so (5,-3) is your original number and when you flip it over the Y axis it would make it (5,3)
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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
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