Answer:
See below ~
Step-by-step explanation:
<u>Things to Find</u>
- Volume of Toy
- Difference of Volumes in Cube and Toy
- Total Surface of Toy
<u>Volume of Toy</u>
- Volume of Hemisphere + Volume (Cone)
- 2/3πr³ + 1/3πr²h
- 1/3πr² (2r + h)
- 1/3 x 3.14 x 16 (8 + 4)
- 1/3 x 50.24 x 12
- 50.24 x 4
- <u>200.96 cm³</u>
<u></u>
<u>Volume of Circumscribing Cube</u>
- Edge length is same as diameter
- V = (8)³
- V = 512 cm³
<u>Difference in Volume</u>
- 512 - 200.96
- <u>311.04 cm³</u>
<u></u>
<u>Slant height of cone</u>
- l² = 4² + 4²
- l² = 32
- l = 4√2 cm = 5.6 cm
<u />
<u>Surface Area of Toy</u>
- CSA (hemisphere) + CSA (Cone)
- 2πr² + πrl
- πr (2r + l)
- 3.14 x 4 (8 + 5.6)
- 12.56 x 13.6
- <u>170.8 cm²</u>
Total number of ways to make a pair:
The first player can be any one of 7 . For each of those . . .
The opponent can be any one of the remaining 6 .
Total ways to make a pair = 7 x 6 = 42 ways .
BUT ... every pair can be made in two ways ... A vs B or B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.
If every pair plays 2 matches, then (21 x 2) = <em><u>42 total matches</u></em> will be played.
Now, is that an elegant solution or what !
Formula:
V = 1/3 * pi * r^2 * h
Plug in what we know:
V = 1/3 * 3.14 * 3^2 * 4
V = 37.68cm^3
So the volume is 37.68cm^3 which rounds to 37.7cm^3.
Answer: No, 8.03 is greater than 8.012