7+5x3-(6-2) divided by 2.explain how you got the answer.
1 answer:
Hey there!
7 + 5(3) - ( 6 - 2) ÷ 2
Let's do PEMDAS to solve this equation!
First step: parentheses → 6 - 2 = 4, right?
Your problem becomes: 7 + 5 (3) - 4
The next step usually would be "e" for the exponents but since we don't have any, we have to move onto Multiplication
5(3) = 15, right?
We have division but we can save that for the last ( you don't have to do this method to solve this equation, by the way!)
Problem becomes: 7 + 15 - 4
Next, we do addition
7 + 15 = 22, right?
Your problem becomes: 22 - 4
Next we do subtraction
22 - 4 = 18, right?
Now we can do division
Good luck on your assignment and enjoy your day!
~
7 + 5(3) - ( 6 - 2) ÷ 2
Let's do PEMDAS to solve this equation!
First step: parentheses → 6 - 2 = 4, right?
Your problem becomes: 7 + 5 (3) - 4
The next step usually would be "e" for the exponents but since we don't have any, we have to move onto Multiplication
5(3) = 15, right?
We have division but we can save that for the last ( you don't have to do this method to solve this equation, by the way!)
Problem becomes: 7 + 15 - 4
Next, we do addition
7 + 15 = 22, right?
Your problem becomes: 22 - 4
Next we do subtraction
22 - 4 = 18, right?
Now we can do division
Good luck on your assignment and enjoy your day!
~
You might be interested in
The graph is attached below.
In order to find the y-intercept, check the graph and see where it hits the y-axis, so in this case the y-intercept would be at (0,6).
To find the x-intercept, check the graph and see where it hits the x-axis, and here it hits at x = -6.
Answer:
Step-by-step explanation:
Given
Rotation = +270 degrees
Required
Determine the new coordinates of Q (i.e. Q')
When a point (x,y) is rotated +270° about the origin, the new coordinates is: (y,−x)
So:
Where:
and
Q' will be: