All categories

3 years ago

Please please help me meeeee please

Mathematics

2 answers:

dimulka [17.4K]3 years ago

8 0

.........................

J=7.01+2.10

J=9.11$

........................

ArbitrLikvidat [17]3 years ago

6 0

Answer:

j=$9.11

Step-by-step explanation:

You might be interested in

A music school offers its students 8 different classes each semester. 4 of the classes are in music theory, 3 of the classes are

Bond [772]

Answer:

Step-by-step explanation:

8 0

2 years ago

HELLOOOOOooOOOOOooOOoooOOoo

Viefleur [7K]

Answer:

6. Multiply 2 by 6

7. 71 + 9(8) = 71 + 72 = 143

8. 52 + 3(4) = 12 + 52 = 64

9. 19.25 + 2.75(7) = 19.25 + 19.25 = 38.50

10. 2(0.6)^2 + 4(0.6)(5) = 0.72 + 12 = 12.72

Srry if they r wrong

6 0

3 years ago

What number must be added to the expression below to complete the square? X^2+5x

Leno4ka [110]

Answer:

25/4

Step-by-step explanation:

x^2 +5x

To complete the square we take (b/2)^2

b =5

(5/2)^2

25/4

7 0

3 years ago

Read 2 more answers

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

1 year ago

HelpPlease!!!<br><br> If s(x)= 2-x2 and t(x)=3 which value is equivalent to s•t(-7)

Shalnov [3]

i think the answer is d

8 0

3 years ago

Read 2 more answers