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Annette [7]
3 years ago
13

Please please help me meeeee please

Mathematics
2 answers:
dimulka [17.4K]3 years ago
8 0

.........................

J=7.01+2.10

J=9.11$

........................

ArbitrLikvidat [17]3 years ago
6 0

Answer:

j=$9.11

Step-by-step explanation:

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Please someone help answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!
kogti [31]

Answer:

z = 44

Step-by-step explanation:

180 - (44+52) = 180 - 96 = 84º

180 - 84 = 96º

180 - (96 + 40) = z

     180 - 136 = z

     z = 44

5 0
3 years ago
Make 80/6 to a mixed number explain how u got your answer
Deffense [45]

Answer:

13\frac{1}{3}

Step-by-step explanation:

The closest multiple of 6 less than 80 is 13.

13×6=78

How many are left over?

80 - 78 = 2

\frac{2}{6} remains, and this can be simplified to \frac{1}{3}

13\frac{1}{3}

Hope this helps!! (I know it sounds a little complicated but it's easy to understand it with practice :)

6 0
3 years ago
Read 2 more answers
Quadrilateral QRST is a rectangle. RT = 5x + 1 and QS = 6x – 3. Find QS.
Kaylis [27]

Answer:

21.

Step-by-step explanation:

RT and QS are diagonals of the rectangle and are equal in length.

5x + 1 = 6x - 3

-x = -4

x = 4

So QS = 6(4) - 3

= 21.

5 0
3 years ago
Read 2 more answers
(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun
finlep [7]

Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that  

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function  that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

a)  

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.  

b)  

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.  

c)  

f(a) = d, f(b) = b, f(c) = c, f(d) = d.  

As in b), since a and d are linked to d, then this function is not one to one. Also, since the element a has no element x in {a,b,c,d} such that f(x) = a, then it also fails to be onto.  

8 0
3 years ago
Drag the correct graph of each equation into the apace next to that equation to show how the output y-values change with changes
Vinvika [58]

Answer:

I can't see the exercise. what do you want?

6 0
3 years ago
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