Step-by-step explanation:
I got this much.....
I am sorry of it gets wrong
To rewrite something as a decimal, simply divide the numerator and denominator.
-33 / 25 = -1.32
So -33/25 = -1.32
Let use h= hotdogs price and c=chips price
we know that
4h +4c= 17
5h+3c=17.75
t use the elimination method we will multiply the first equation by 5 and the second one by (-4)
20h +20c=85
-20h -12c= -71
8c=14, we will divide by 8 both side and c=1.75, so a bag of potato chips cost $ 1.75
now we will substitute the c in the first equation
4h+7=17 therefore 4h=17-7, 4h=10, h=2.50
a bag of potato chips is 1.75
a hot dog costs 2.50
Opposite sides of a parallelogram are equal lengths, so ...
... AB = CD
... 6x +30 = 2y -10
and
... BC = AD
... 2x -5 = y -35
_____
The equations can be put in standard form to get
... 3x -y = -20
... 2x -y = -30
Subtracting the second from the first, we get
... x = 10
Solving for y, we have
... y = 2x+30 = 2·10 +30 = 50
The values of x and y are x=10, y=50.
_____
AB = 6x+30 = 90
BC = 2x-5 = 15
Answer:
![\sqrt[n]{a} =a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Explanation:
Roots of real numbers can be represented by <em>radicals</em> or by<em> exponents. </em>
First, I present some examples to show how exponents and radicals are related, and then generalize.
![\sqrt[3]{8}=(8)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}=(2)^{\frac{3}{3}}=2^1=2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%3D%288%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%282%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%282%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3D2%5E1%3D2)
When you write 5² = 25, then 5 is the square root of 25.
And in general, if n is a positive integer and 
, then 
is the nth root of x.
Also, if n even (and positive) and is positive, then 
is the positive nth root of
Thus,
