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Arada [10]
2 years ago
9

Hii please help i’ll give brainliest if you give a correct answer!

Mathematics
2 answers:
docker41 [41]2 years ago
8 0

Answer:

It depends... look at the bottom of my explanation

Step-by-step explanation:

5\frac{1}{3}=\frac{31}{3}   — I converted this to an improper fraction to make this easier; the 30 added to the 1 in the numerator comes from multiplying 5 by the denominator, 3, to create an equivalent number.

³¹/₃ ÷ ²/₃  — Now we divide the two fractions.

³¹/₃ × ³/₂  — Dividing by one fraction is the same as multiplying by its reciprocal

³¹/₁ × ¹/₂  — One fraction has a 3 in its numerator, the other in its denominator. These two "3" values cancel out

31 ÷ 2  — simplifying the resulting expression

³¹/₂ = 15.5  — two other ways to rewrite it; 15.5 comes from dividing 31 by 2

Now, she can't make <em>part</em> of a batch... could she? If she can, it's 15.5. If she can't, she can make 16 or 15 batches depending on how you round.

That's a judgment call. But I hope you understand this better! Have a great day!

Vanyuwa [196]2 years ago
3 0

I'm not sure if this dividing,multiplying,subtracting or adding but for adding i got 6 as my answer.I don't know if this the correct answer but its better than having no answer right?

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7/6

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6/7 * 7/6= 1

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32x - 24y - 5

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Describe the relationship between n and 4 that will make the value of the expression 7xn4greater than7
valina [46]

Answer:

As per the statement: the value of the expression 7 x n/4 greater than 7.

To describe the relationship between n and 4.

"greater than" symbol is represented by '>'

The value of expression 7 \times \frac{n}{4} grater than 7 is;

7(\frac{n}{4}) > 7

Divide by 7 both sides we get;

\frac{n}{4} > 1

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8 0
3 years ago
The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
2 years ago
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