Answer:
The correct answer is e3
Explanation:
The given protein in the question proteib X contain four subunits of equal size alpha,beta,delta and gamma which are bound by either noncovalent interactions or disulfide bridges and only beta and delta subunits are bound to each other by disulfide bridges.
As a result when the protein will undergo fragmentation it will generate 3 bands because the interaction that is present between alpha and beta subunit will break resulting in the formation of 2 bands. Now the most important fact is that the beta subunit is linked to delta subunit by di sulfide bond so when betamarcaptoethanol will act on protein X it will break the disulsulfide bond present between the beta and delta subunit to reduce both the subunit.
Finally the interaction that is present between delta subunit and gamma subunit will be broken down to release the delta subunit which will form a single band during SDS PAGE..
Answer:
The genotype for each of the parents must be
parent 1 : Gg
parent 2 : Gg
Explanation:
Please note that a dominant trait is a trait that is expressed phenotypically in a heterozygous state, while a recessive trait is a trait that can only be expressed in a homozygous state.
Now, since gray face (G) for Oompa Loompas is dominant, and orange face (g) is recessive, for an offspring to be orange faced, it means that the genotype of the offspring must be 'gg'. Also, since both parent contribute an allele in the pair of alleles in the offspring, both parents must have the recessive (g) in their genotype. Moreover, we are told that both parents are gray-faced, meaning that their genotypes were 'Gg' and 'Gg'. To confirm, let me do the cross
G g
G GG Gg
g Gg gg
from the cross above, we find out that out of 4 offspring, 3 were gray face (GG, Gg ) while one was orange face (gg).
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