<em>Answer: A solution to a system of equations means the point must work in both equations in the system. So, we test the point in both equations. It must be a solution for both to be a solution to the system. Hope this helps.</em>
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<em>I hope it helps if it does can please mark me as Brainliest thank you!</em>
Answer:
M=3
Step-by-step explanation:
Use the slope formula
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Answer:
300
Step-by-step explanation:
A significant figure is the most important (largest) number you can round it to.
As it wants 1 significant figure, you count 1 to the left and round the 4 down.
Hope this helps :)
Given:
A directed line segment begins at F(-8, -2), ends at H(8, 6), and is divided in the ratio 8 to 2 by G.
To find:
The coordinates of point G.
Solution:
Section formula: If a point divide a line segment with end points 
and 
in m:n, then the coordinates of that point are
Point G divide the line segment FH in 8:2. Using section formula, we get
Therefore, the coordinates of point G are (4.8, 4.4).
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
