Answer:
(x-1)²+(y-3)²=65
Step-by-step explanation:
the common view of the equation of a circle is:
a) (x-a)²+(y-b)²=r², where (a;b) - the centre of the required circle, r - the radius of the required circle;
b) using the coordinates of the endpoint of the given diameter it is possible to calculate the coordinates of the centre of the required circle and its radius²:
the coordinate x of the required circle is: (9-7)/2=1;
the coordinate y of the required circle is: (2+4)/2=3.
the radius² of the required circle is:
r²=0.25*[(9- -7)²+(2-4)²]=0.25*260=65.
c) after the substitution the values of 'a'; 'b' and 'r²' into the common equation of the circle:
(x-1)²+(y-3)²=65.
PS. additional: the given points (9;2) and (-7;4) belong to the final equation, if to substitute their coordinates into it.
The suggested way of solution is not the only one.
Hello :
<span>the parabola's equation is : f(x) = a(x+3)²-1
</span><span>the coefficient of the squared expression in the parabola's equation is : a
but ; f(4) = 0
0 = a(4+3)²-1
49a-1=0.....a=1/49
f(x) = 1/49(x-3)²-2</span>
Answer:
true!
Step-by-step explanation:
plug in 1.1
3 + 51(1.1) = 59.1
3 + 56.1 = 59.1
59.1=59.1
Answer:
D: 0 and 1
Step-by-step explanation:
Function is defined by;
f(x) = 3x^(5) - 5x⁴
Now, an inflection point will be a point on the graph where the inflection or concavity changes.
Thus, let's find the derivatives until we get there;
f'(x) = 15x⁴ - 20x³
f''(x) = 60x³ - 60x²
So factorizing gives;
f''(x) = 60x²(x - 1)
At f''(x) = 0, we have; x = 0 or x = 1
Thus, the x coordinates of points of inflection are 0 & 1