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Lelechka [254]
3 years ago
14

Sylvia walked​ 34 ​mi east from her house to the bank. Then she walked 13 ​mi west to a gift shop. From the gift shop, she walke

d​ 14 ​mi west to a grocery store. How far is the grocery store from Sylvia's house?
Mathematics
1 answer:
Oduvanchick [21]3 years ago
5 0
I'm thinking it is a mile from her house
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I have a question for you
egoroff_w [7]

Answer:

10 5/6

Step-by-step explanation:

First we have to make 2 1/6 into an improper fraction. This can be rewritten as 13/6. Now, we can multiply 13 by 5 and get 65/6. If we re-convert this into a mixed number, 6 goes into 65 10 times with a remainder of 5, so the final answer is 10 5/6.

4 0
3 years ago
Is 1 1/4 + 1 1/4 = 2 3/4 correct?
laila [671]

Answer:

no

Step-by-step explanation:

11/4 plus 11/4 is 22/4

to make this a whole number and a fraction we subtract 4 from the 22 as many times as we can. we can do this 5 times, with 2 left over.

the answer is 5 2/4, which you can simplify to 5 and a half

7 0
3 years ago
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What numbers multiply to give me 12 but add to give me -7
romanna [79]

Answer:

-4 and -3

A negative times a negative results to a positive number, but when two negative numbers are added to each other, it still results to a negative number.

Hope I helped!

5 0
3 years ago
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I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
sweet T has 2 orange picks for every 5 green.If there are 21 picks in all,How many picks are orange?
kipiarov [429]
6 of the picks are orange.
8 0
3 years ago
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