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solmaris [256]
3 years ago
8

Evaluate (y - 9) + (3 + x), when y = 15 and x = 5​

Mathematics
1 answer:
svet-max [94.6K]3 years ago
5 0

Answer:

14

Step-by-step explanation:

It says 'Evaluate (y - 9) + (3 + x), when y = 15 and x = 5​'.

So we'd put 15 in y's place. It'll look like this (15 - 9).

Then we'd put 5 in x's place. It'll look like this (3 + 5).

You subtract (15 - 9) which equals 6. And you'd add (3 +5) which equals 8. You add 6 + 8 together since those are your answer for the parentheses. Your final should be 14. Hopefully this helped!

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Explain how mental math can be used to estimate a 15% tip on a taxi ride that costs $23.25 Find the tip using that method. Halp
gizmo_the_mogwai [7]

Answer:

$3.4875

Step-by-step explanation:

AS the ride is completed and according the rule the person have to give a tip on the total taxi ride

according to the given

tip given 15%

Total ride cost = $23.25

To find is the total tip given in dollars

Solution:

Total tip in dollars = 15 % of total ride cost

Putting the values of the given

Total tip in dollars = 15 % of 23.25

it can be written as

                             = \frac{15*23.25}{100}

                              =\frac{348.75}{100}

                               =$ 3.4875

So the total tip would be $3.4875

7 0
3 years ago
A quarter is 1/5 of an inch thick and 5 quarters weigh one ounce. Stephanie built a toothpick bridge that could safely hold 3 po
AleksandrR [38]

Answer:

Maximum height of quarter tower = 9.6 inches.

Step-by-step explanation:

The thickness of a quarter = \frac{1}{5} inches

Weight of a quarter = 1 ounce

The maximum weight that could safely hold = 3 pounds.

<u>The conversion factor for ounce to pound is 1 ounce = 0.0625 pound</u>

The number of quarter used in the tower = no of ounces equivalent to 3 pounds.

No of ounces equivalent to 3 pounds = \frac{3}{0.0625}

No of ounces equivalent to 3 pounds = 48

So the height of quarter tower = 48 \times \frac{1}{5} inches

                                                   = 9.6 inches.

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3 years ago
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12k + 26 factor completely<br><br>pls help ​
Liula [17]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
3 years ago
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