Answer:
the answer is 8/3
Step-by-step explanation:
-2/3 ÷ 1/-4
-2/3 × -4/1
8/3
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Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So,
is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So,
would be 25°.
Now we can find
. As the sum of the internal angle of a triangle is 180°.

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
a
Step-by-step explanation:
1/4 5 time is 5/4 and if you multiply by - there will be negative on the product.
Answer: <em>(1,5,7,10,11,15)</em>
To get the union of two sets of numbers, all you do is combine the numbers from least to greatest. If a number repeats in the 2 sets, you only put it once.
Answer:
AAS
Step-by-step explanation: