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jeka57 [31]
3 years ago
10

Which conjunction about whole numbers is true?

Mathematics
1 answer:
son4ous [18]3 years ago
7 0

Answer:

The sum of two non-zero even numbers is even and greater than the addends

Step-by-step explanation:

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Prove that:
devlian [24]

Answer:

<u>Identities used:</u>

  • <em>1/cosθ = secθ</em>
  • <em>1/sinθ = cosecθ</em>
  • <em>sinθ/cosθ = tanθ</em>
  • <em>cosθ/sinθ = cotθ</em>
  • <em>sin²θ + cos²θ = 1</em>
<h3>Question 1 </h3>
  • (1 - sinθ)/(1 + sinθ) =        
  • (1 - sinθ)(1 - sinθ) / (1 - sinθ)(1 + sinθ) =
  • (1 - sinθ)² / (1 - sin²θ) =
  • (1 - sinθ)² / cos²θ

<u>Square root of it is:</u>

  • (1 - sinθ)/ cosθ =
  • 1/cosθ - sinθ / cosθ =
  • secθ - tanθ
<h3>Question 2 </h3>

<u>The first part without root:</u>

  • (1 + cosθ) / (1 - cosθ) =
  • (1 + cosθ)(1 + cosθ) / (1 - cosθ)(1 + cosθ)
  • (1 + cosθ)² / (1 - cos²θ) =
  • (1 + cosθ)² / sin²θ

<u>Its square root is:</u>

  • (1 + cosθ) / sinθ =
  • 1/sinθ + cosθ/sinθ =
  • cosecθ + cotθ

<u>The second part without root:</u>

  • (1 - cosθ) / (1 + cosθ) =
  • (1 - cosθ)²/ (1 + cosθ)(1 - cosθ) =
  • (1 - cosθ)²/ (1 - cos²θ) =
  • (1 - cosθ)²/sin²θ

<u>Its square root is:</u>

  • (1 - cosθ) / sinθ =
  • 1/sinθ - cosθ / sinθ =
  • cosecθ - cotθ

<u>Sum of the results:</u>

  • cosecθ + cotθ + cosecθ - cotθ =
  • 2cosecθ
4 0
3 years ago
Read 2 more answers
Can anybody help me with this
kondaur [170]

Answer:

c ≈ 9.1 m

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

c² = 4.1² + 8.1² = 16.81 + 65.61 = 82.42 ( take square root of both sides )

c = \sqrt{82.42 } ≈ 9.1 m ( to the nearest tenth )

5 0
2 years ago
Please help with steps, will give brainliest. Simplify
kumpel [21]

Answer:

=53*(54 ×^9 y^12 z^15)^1/2

=53*y^6 *z^(15/2) * x^( 9/2)* (54)^1/2

4 0
2 years ago
The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.
zhuklara [117]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(t)=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{19}t+110~\hspace{10em}19~\frac{ft}{sec}

3 0
3 years ago
Q3. Express 984. 6080 correct to
const2013 [10]

Answer:

a) 984.6080 = 984.61 to 2 decimal places

b) 984.6080 = 984.6 to 4 significant figures

c) 984.6080 = 984.608 to 3 decimal places

d) 984.6080 = 984.61 to the nearest hundredth

Step-by-step explanation:

Answers to the approximation questions above are supplied below.

First, you needs to know approximation processes:

Step 1: Keep the required number of digits in question.

Step 2: Before rounding off the remaining digits, look at the next digit to the required number of accuracy, if it is 5 or more, increase the last digit of the number you're keeping by 1, otherwise leave it as it is and round down to zero all the unwanted digits.

Similarly, there is need know the meaning of each degree of accuracy.

1. Decimal places: These are the number of digits occurring after the decimal point. E.g. a set of figures in 1 decimal place has only one digit after decimal point, i.e. 65.4. In the case of the question above,

a) 984.6080 = 984.61 to 2 decimal places

c) 984.6080 = 984.608 to 3 decimal places

2. Significant figures: Basically, these are nonzero digits in a set of figures. However, when zero is in the middle of nonzero digits, i.e, 3045, such zero is a significant figure. In the question above,

b) 984.6080 = 984.6 to 4 significant figures

3. Hundredth: Under place value system, hundredth of a set of figures is located at two digits after the decimal point. In other words, hundredth is same as two decimal places so the same approach is required for the two. Thus;

d) 984.6080 = 984.61 to the nearest hundredth

You can see that the result for both 2 decimal places and nearest hundredth are the same, that is, 984.6080 = 984.61 to 2 decimal places and to the nearest hundredth respectively.

Therefore, the answers are summarized thus:

a) 984.6080 = 984.61 to 2 decimal places

b) 984.6080 = 984.6 to 4 significant figures

c) 984.6080 = 984.608 to 3 decimal places

d) 984.6080 = 984.61 to the nearest hundredth

5 0
3 years ago
Read 2 more answers
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