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Shkiper50 [21]
3 years ago
10

Which expression is equivalent to (xy^-6)^2

Mathematics
1 answer:
Furkat [3]3 years ago
4 0

Answer:

\huge\boxed{\left(xy^{-6}\right)^2=x^2y^{-12}=\dfrac{x^2}{y^{12}}}

Step-by-step explanation:

\left(xy^{-6}\right)^2=x^2\left(y^{-6}\right)^2=x^2y^{-6\cdot2}=x^2y^{-12}=\dfrac{x^2}{y^{12}}

Used

(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}

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Softa [21]

Answer:

The answer is C. How many 3/4 -pound molds are in 1/3 pound of sand?

7 0
3 years ago
Read 2 more answers
Two basketballs are thrown along different paths. Determine if the basketballs’ paths are parallel to each
Paul [167]

Answer:

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

Step-by-step explanation:

Remember that:

  • Two lines are parallel if their slopes are equivalent.
  • Two lines are perpendicular if their slopes are negative reciprocals of each other.
  • And two lines are neither if neither of the two cases above apply.

So, let's find the slope of each equation.

The first basketball is modeled by:

\displaystyle 3x+4y=12

We can convert this into slope-intercept form. Subtract 3<em>x</em> from both sides:

4y=-3x+12

And divide both sides by four:

\displaystyle y=-\frac{3}{4}x+3

So, the slope of the first basketball is -3/4.

The second basketball is modeled by:

-6x-8y=24

Again, let's convert this into slope-intercept form. Add 6<em>x</em> to both sides:

-8y=6x+24

And divide both sides by negative eight:

\displaystyle y=-\frac{3}{4}x-3

So, the slope of the second basketball is also -3/4.

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

3 0
3 years ago
Which step is wrong, Step 1, Step 2, Step 3 or Li didn't make a mistake
mart [117]
Hello there!


The correct answer is option A

Instead of the division sign, it suppose to be multiply.

Have fun on Khan Academy!
7 0
3 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
2 years ago
A pair of boots is on sale for 1/4 off the original price. The sale price is $70.50. What is the original price of the boots?
Iteru [2.4K]

Answer: 282

Step-by-step explanation: just multiplícate it by 4

4 0
3 years ago
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