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Troyanec [42]
3 years ago
14

Henry wants to join a book-of-the-month club. The first club costs $40 to join and $10 per book. The second club costs $15 per b

ook and has no fee to join. How many books would need to be purchased from each club for the clubs to cost the same?
Mathematics
2 answers:
Marta_Voda [28]3 years ago
7 0

Answer:

There would have to be 2 books purchased from the first club. Then, there would have to be 4 books purchased from the second club.

Step-by-step explanation:

1st club.  (cost of club) 40$ + (cost of 2 books) 20$ = 60$.

2nd club. (cost of books) 15$ x  (how many books) 4 = 60$

arsen [322]3 years ago
4 0

Answer:

Step-by-step explanation:

For club 1 - 2 book

For club 2 - 4 books

Club 1 has a $40 fee + 2 books = $60 in total

Club 2 has a $0 fee + 4 book = $60 in total

I'm pretty sure I'm right

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In a collection of nickels, dimes, and quarters worth $6.90, the ratio of the number of nickels to dimes is 3:8. The ratio of th
dimulka [17.4K]
N=number of nickels
d=number of dimes
q=number of quarters

example
if n:d=3:8
lets say n=3 and d=8
3*8=8*3
so
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slightly confusing but go with it, it migh make sense or it might not


n:d=3:8
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solve for one of them
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8n=3d, n=(3/8)d
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divide by 5 to make it easeir
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3/8+2+25/4=
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sub back

(5/4)d=q
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(3/8)d=n
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6=n



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