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Troyanec [42]
2 years ago
14

Henry wants to join a book-of-the-month club. The first club costs $40 to join and $10 per book. The second club costs $15 per b

ook and has no fee to join. How many books would need to be purchased from each club for the clubs to cost the same?
Mathematics
2 answers:
Marta_Voda [28]2 years ago
7 0

Answer:

There would have to be 2 books purchased from the first club. Then, there would have to be 4 books purchased from the second club.

Step-by-step explanation:

1st club.  (cost of club) 40$ + (cost of 2 books) 20$ = 60$.

2nd club. (cost of books) 15$ x  (how many books) 4 = 60$

arsen [322]2 years ago
4 0

Answer:

Step-by-step explanation:

For club 1 - 2 book

For club 2 - 4 books

Club 1 has a $40 fee + 2 books = $60 in total

Club 2 has a $0 fee + 4 book = $60 in total

I'm pretty sure I'm right

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The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The distance from point C to point D is 258.8 meters.

<h3>What is Tangent (Tanθ)?</h3>

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,

\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

The distance from point C to D is equal to the distance from point A to B. Therefore, the height of the building can be written as,

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Tan(25°) × 555 m = AB

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2 years ago
Which postulate or theorem can be used to
sveticcg [70]

Answer:

AA Similarity Postulate

Step-by-step explanation:

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step 1

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\frac{PS}{PQ}=\frac{PT}{PR}

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\frac{45}{20}=\frac{36}{16}

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m\angle PRQ=m\angle PTS --> by corresponding angles

so

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\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \  2x^3-7x^2+8x-3=0 } \end{gathered}$}

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  | 2  -7    8  -3

<u>1 |      2   -5   3</u>

  | 2   -5    3  0

<u> 1 |      2     -3   </u>

    2   -3     0

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  <u>2  |     2  2     </u>

         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

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<u>-2 |      -12    10     -2</u>

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2 years ago
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