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3 years ago

Is due today !! need help (show work/explanation)

Mathematics

2 answers:

Lady_Fox [76]3 years ago

7 0

Answer:

Step-by-step explanation:

radius=diameter/2

=8/2

=4 m

volume of a cylinder =πr^2h

=3.14*(4)^2*13

=40.82*16

=653.12 m^3

alina1380 [7]3 years ago

5 0

653. 12^3
blahblahblag

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Mike found 74 seashells on the beach, he gave Mary some of his

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Answer:

48 seashells

Step-by-step explanation:

you subtract 74-26 to get 48. to check your answer you do 74-48 to get 26.

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Jane was baking cookies. She needed 1/3 cup sugar and 1 2/4 cups flour. How much more flour does she need than sugar?

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Answer:

1 and 1/6 cups more

Step-by-step explanation:

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2 years ago

HELP ASAP 10 POINTS TO BRAINLIEST

Brilliant_brown [7]

Answer:

15%

Step-by-step explanation:

The cost of 2 adults and 2 children without the discount is

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6 0

3 years ago

There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of

Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

$AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta$ (1)

Where:

$AC$ - The distance from A to C, measured in miles.

$AB$ - The distance from A to B, measured in miles.

$BC$ - The distance from B to C, measured in miles.

$\theta$ - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

$AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta$

$\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}$

$\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right)$ (2)

If we know that $BC = 7\,mi$ , $AB = 8\,mi$ , $AC = 5\,mi$ , then the bearing from island B to island C:

$\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]$

$\theta \approx 38.213^{\circ}$

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0

3 years ago