Answer:
Hello your question is incomplete attached below is the correct question
and the solution
answer: A
Step-by-step explanation:
attached below is a detailed solution of the given problem
There exists P and C such that ( ∵ λ1 ≠ λ21 so A is diagonalizable )
Assume the smaller one is x, then the other ones will be x+2 and x+4
x(x+2) + 2 = 5(x+4)
x^2 + 2x - 5x - 18 = 0
-> x^2 - 3x - 18 = 0
-> (x-6)(x+3) = 0
-> x = 6 or -3, since x must be positive, then x = 6
So the numbers are: 6, 8, 10
Answer:
3.7
Step-by-step explanation:


Hope this helps