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3 years ago

2. How do light waves differ from sound waves and water waves?

Physics

2 answers:

mina [271]3 years ago

7 0

Sound and water waves are mechanical waves, unlike light waves.

Basile [38]3 years ago

3 0

Answer:

Light waves are electromagnetic waves while sound waves are mechanical waves. Light waves are transverse while sound waves are longitudinal. Light waves can travel in vacuum. Sound waves require a material medium to travel, and hence, cannot travel in vacuum.Water waves are surface waves, a mixture of longitudinal and transverse waves.

Explanation:

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How fast must a 2.70-g ping-pong ball move in order to have the same kinetic energy as a 145-g baseball moving at 31.0 m/s

Helen [10]

Answer:

227 m/s

Explanation:

Kinetic energy formula:

$\displaystyle \text{KE} = \frac{1}{2} mv^2$

where m = mass of the object (kg)
and v = speed of the object (m/s)

Let's find the kinetic energy of the 145-g baseball moving at 31.0 m/s.

First convert the mass to kilograms:

145-g → 0.145 kg

Plug known values into the KE formula.

$\displaystyle \text{KE} = \frac{1}{2} (.145)(31.0)^2$
$\displaystyle \text{KE} = 69.6725 \ \text{J}$

Now we want to find how fast a 2.70-g ping pong ball must move in order to achieve a kinetic energy of 69.6725 J.

First convert the mass to kilograms:

2.70-g → 0.00270 kg

Plug known values into the KE formula.

$\displaystyle 69.6725 = \frac{1}{2} (.00270)v^2$
$\displaystyle \frac{2(69.6725)}{.00270} =v^2$
$57609.25926=v^2$
$v=227.1767137$

The ping-pong ball must move at a speed of 227 m/s to achieve the same kinetic energy as the baseball.

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A radio has a 1.3 A current. If it has a resistance of 35 Ω, what is the potential difference?

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A volleyball is spiked so that it has an initial velocity of 17.6 m/s directed downward at an angle of 51.3 ° below the horizont

nata0808 [166]

<u>Answer:</u>

Horizontal component of the velocity when the opposing player fields the ball = 11.00 m/s

<u>Explanation:</u>

The velocity of a body in 2 dimension can be resolved in to 2 parts, horizontal and vertical component. In the case of free falling or projectile body the horizontal component remains the same but vertical component is affected by acceleration due to gravity.

In this case Initial velocity = 17.6 m/s

Angle between horizontal axis and direction of velocity = 51.3 °

We know that horizontal component = v cos θ

Vertical component = v sin θ

Since the horizontal component remains the same, it is unchanged when the opposing player fields the ball.

So horizontal component of the velocity = v cos θ = 17.6 * cos 51.3 °

= 11.00 m/s

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