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Harman [31]
3 years ago
6

A radio has a 1.3 A current. If it has a resistance of 35 Ω, what is the potential difference?

Physics
2 answers:
DedPeter [7]3 years ago
7 0

Answer:

22

Explanation:

lidiya [134]3 years ago
3 0

Answer:

45.5 v

Explanation:

I = 1.3 A

R = 35 Ω

V = I * R

V = 1.3 * 35 = 45.5 v

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If the velocity of a pitched ball has a magnitude of 44.5 m/s and the batted ball's velocity is 55.5 m/s in the opposite directi
Lelu [443]

Answer:

ΔP = 14.5 Ns

I = 14.5 Ns

ΔF = 5.8 x 10³ N = 5.8 KN

Explanation:

The mass of the ball is given as 0.145 kg in the complete question. So, the change in momentum will be:

ΔP = mv₂ - mv₁

ΔP = m(v₂ - v₁)

where,

ΔP = Change in Momentum = ?

m = mass of ball = 0.145 kg

v₂ = velocity of batted ball = 55.5 m/s

v₁ = velocity of pitched ball = - 44.5 m/s (due to opposite direction)

Therefore,

ΔP = (0.145 kg)(55.5 m/s + 44.5 m/s)

<u>ΔP = 14.5 Ns</u>

The impulse applied to a body is equal to the change in its momentum. Therefore,

Impulse = I = ΔP

<u>I = 14.5 Ns</u>

the average force can be found as:

I = ΔF*t

ΔF = I/t

where,

ΔF = Average Force = ?

t = time of contact = 2.5 ms = 2.5 x 10⁻³ s

Therefore,

ΔF = 14.5 N.s/(2.5 x 10⁻³ s)

<u>ΔF = 5.8 x 10³ N = 5.8 KN</u>

4 0
3 years ago
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains
Vikki [24]
Hey i dont have an answer but i need the points for finals today. Thank you
6 0
3 years ago
Read 2 more answers
Imagine that a hypothetical life form is discovered on our moon and transported to Earth. On a hot day, this life form begins to
almond37 [142]

Answer:

The heat of vaporization 580 cal/g times 602g = cal in human  and do the same for life form.

Explanation:

4 0
3 years ago
A key falls from a bridge that is 32 m above the water. It falls directly into a model boat, moving with constant velocity, that
FinnZ [79.3K]

Answer:

Speed of the boat, v = 4.31 m/s

Explanation:

Given that,

Height of the bridge, h = 32 m

The model boat is 11 m from the point of impact when the key was released, d = 11 m

Firstly, we will find the time needed for the boat to get in this position using second equation of motion as :

s=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

t=\sqrt{\dfrac{2s}{g}}

t=\sqrt{\dfrac{2\times 32}{9.8}}

t = 2.55 seconds

Let v is the speed of the boat. It can be calculated as :

v=\dfrac{d}{t}

v=\dfrac{11\ m}{2.55\ s}

v = 4.31 m/s

So, the speed of the boat is 4.31 m/s. Hence, this is the required solution.

3 0
3 years ago
Action-reaction forces are not balanced forces because of what?
lara [203]

Oh but they are !

Newton's 3rd law of motion says that for every action, the <em><u>re</u></em>action is
equal and opposite.  That's as balanced as you can get.


4 0
3 years ago
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