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Serga [27]
3 years ago
11

Suggest two uses of pulleys.

Physics
1 answer:
Marizza181 [45]3 years ago
8 0

Answer: Elevators use pulleys to function.

A cargo lift system that allows for items to be hoisted to higher floors is a pulley system.

Explanation:

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. Potential energy is a vector quantity True or false?
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A car is moving with speed 20 m/s and acceleration 2 m/s2 at a given instant. Using a second-degree Taylor polynomial, estimate
PilotLPTM [1.2K]

Answer:

T(1)=21

Explanation:

The equation of the position in kinematics is given:

x(t)=x_{0}+v_{0}t+0.5at^{2}

  • x(0) is the initial position, in this it is 0
  • v(0) is the initial velocity (20 m/s)
  • a is the acceleration (2 m/s²)

So the equation will be:

x(t)=20t+0.5*2*t^{2}

x(t)=20t+t^{2}    

Now, the Taylor polynomial equation is:

f(a)+\frac{f'(a)}{1!}(x-a)+\frac{f''(a)}{2!}(x-a)^{2}+...

Using our position equation we can find f'(t)=v(t) and f''(x)=a(t). In our case a=0, so let's find each derivative.

f(t)=x(t)=20t+t^{2}

f'(t)=\frac{dx(t)}{dt}=v(t)=20+2t

f''(t)=\frac{dv(t)}{dt}=a(t)=2

Using the Taylor polynomial with a = 0 and take just the second order of the derivative.

f(0)+\frac{f'(0)}{1!}(x)+\frac{f''(0)}{2!}(x)^{2}

f(0)=x(0)=0

f'(0)=v(0)=20

f''(0)=a(0)=2

T(t)=f(0)+\frac{f'(0)}{1!}(t)+\frac{f''(0)}{2!}(t)^{2}

T(t)=\frac{20}{1!}(t)+\frac{2}{2!}(t)^{2}

T(t)=20t+t^{2}

Let's put t=1 so find the how far the car moves in the next second:

T(1)=20*1+1^{2}

T(1)=21

Therefore, the position in the next second is 21 m.

We need to know if the acceleration remains at this value to use this polynomial in the next minute, so I suggest that it would be reasonable to use this method just under this condition.

I hope it helps you!

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3 years ago
To fight a bacterial infection, a patient was given an antibiotic to take for 10 days. After the patient finished taking the ant
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3 years ago
Read 2 more answers
The garcias like to keep their 40.0 watts front prch light on at night to welcome visitors. if the light is on from 6pm until 7a
Gnesinka [82]

Answer:

For 1 week total cost will be equal to 0.2912

Explanation:

We have given power P = 40 watt

Light is on from 6 pm to 7 am

So total time = 13 hours

We know that energy is given by

Energy=power\times time

So energy will be E=40\times 13=520watt-hour=0.520Kwh

We have given cost per KWh is 0.08

So total cost per day will be = 0.08 ×0.520 = 0.0416

For 1 week that is for 7 day total cost will be = 7×0.0416 = 0.2912

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4 years ago
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