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valina [46]
3 years ago
15

Write the standard form of the equation of a circle with a radius of 1 and a center of (-7,1)

Mathematics
2 answers:
Lynna [10]3 years ago
6 0
Answer= (x+7)^2 +(y-1)^2 =1

Standard form of a circle:
(x-h)^2 + (y-k)^2 = r^2
yan [13]3 years ago
5 0

Answer:

(x + 7)² + (y - 1)² = 1

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 7, 1) and r = 1 , then

(x - (- 7) )² + (y - 1)² = 1² , that is

(x + 7)² + (y - 1)² = 1

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Please help me with the 3rd question!!! I'll give you 91 points now, please.
saw5 [17]

Answer:

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Step-by-step explanation:

So first of all you need to find out how many even numbers there are from 1-900 (which is 450) so you know that 450 are open. In the 3 multiplication tables every second number is even so you know that half of the 450 lockers that was opened was closed again: this meant that 225 lockers remained open.

You also know that every number in the 4 multiplication tables is the second number in the 2 multiplication tables so half of them are closed but you also know that the 900th locker was opened so now you have 113.

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Answer:

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Step-by-step explanation:

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3 years ago
It says factor 49x-28
kvasek [131]

Answer:

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Step-by-step explanation:

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6 0
4 years ago
Read 2 more answers
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Alexxx [7]

Answer:

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Yakvenalex [24]

Answer:

d=10

Step-by-step explanation:

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