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Basile [38]
3 years ago
13

What is the output? answer = "Hi mom print(answer.lower()) I​

Computers and Technology
1 answer:
DerKrebs [107]3 years ago
3 0
As you have included a syntax error inside your question, I will make assumptions on the code. I will assume your code is {
answer = “Hi mom”
print(answer.lower())
}

In this case the output would be “hi mom”. Please make sure to double check your questions before posting.
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She wanted to impress her friends with the latest phone.

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you have a website that customers use to view product information and place orders. You would like to identify the maximum numbe
notka56 [123]

Answer:

a load tester.

Explanation:

Based on the information provided within the question it can be said that in this situation the tool that you should use is known as a load tester. This tool allows you to test your servers in order to see how it behaves under both normal conditions as well as the anticipated peak load conditions that it may be encountering in the near future. Which is exactly what you need for your website.

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In an attempt to reach an all-time record for its premier, ads for the highly anticipated Avengers: Endgame are run on all the m
cricket20 [7]

Based on the contextual situation, the cable stations across the country from 8:00 p.m. to 10:00 p.m., or during <u>Late-fringe time</u>.

<h3>What is Late-Fringe Time?</h3>

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Generally, the prime period is usually between 8:00 p.m. to 10:00 p.m., while the Late Fringe time is around 11 p.m. to 1 a.m.

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8 0
2 years ago
Create a function called makePositive that accepts a single argument: an integer array. The function should walk through the arr
coldgirl [10]

Answer:

This solution is implemented in C++

void makePositive(int arr[]){

   int i =0;

   while(arr[i]!=0){

       if(arr[i]<0){

           arr[i] = abs(arr[i]);

       }

       i++;

   }

   i = 0;

   while(arr[i]!=0){

    cout<<arr[i]<<" ";

    i++;

}  

}

Explanation:

This defines the function makePositive

void makePositive(int arr[]){

This declares and initializes i to 0

   int i =0;

The following iteration is repeated until the last element in the array

   while(arr[i]!=0){

This checks if current array element is negative

       if(arr[i]<0){

If yes, it changes it to positive

           arr[i] = abs(arr[i]);

       }

The next element is then selected

       i++;

   }

This sets i to 0

   i = 0;

The following iteration prints the updated content of the array

<em>    while(arr[i]!=0){ </em>

<em>     cout<<arr[i]<<" "; </em>

<em>     i++; </em>

<em> }   </em>

}

See attachment for full program which includes the main

Download cpp
8 0
3 years ago
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