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3 years ago

3+(-4) on a number line iready

Mathematics

1 answer:

natka813 [3]3 years ago

6 0

Answer:

it minus one or -1

Step-by-step explanation:

because 4 has more minus than 3 plus

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How many solutions does the system have? y = -2x-4 \\\\ y = 3x+3

lakkis [162]

Answer:

The system has one solution.

Step-by-step explanation:

We have two equations:

y = -2x - 4

y = 3x + 3

Equalling them:

y = y

-2x - 4 = 3x + 3

5x = -7

$x = -\frac{7}{5}$

And

$y = 3x + 3 = 3(-\frac{7}{5}) + 3 = \frac{-21}{5} + 3 = \frac{-21}{5} + \frac{15}{5} = -\frac{6}{5}$

Replacing in the other equation we should get the same result.

$y = -2x - 4 = -2(-\frac{7}{5}) - 4 = \frac{14}[5} - 4 = \frac{14}{4} - \frac{20}{5} = -\frac{6}{5}$

So the system has one solution.

3 0

3 years ago

Doune Punowing:

nataly862011 [7]

The length of pathway is 10 inches on map.

Step-by-step explanation:

Given,

Total distance = 350 miles

According to map,

1 inch = 35 miles

Let, x be the number of inches on map.

Therefore, using proportion;

Inch : mile :: inch : mile

$1:35::x:350\\$

Product of mean = Product of extreme

$35*x=350*1\\35x=350\\$

Dividing both sides by 35;

$\frac{35x}{35}=\frac{350}{35}\\x=10$

The length of pathway is 10 inches on map.

Keywords: Ratio, proportion

Learn more about proportions at:

#LearnwithBrainly

8 0

3 years ago

Find the slope of the line.

Aloiza [94]

Answer: y=1x-1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$