Question

What is the factored form of 125x6 – 8?

Answer 1

Hello,

Answer C

(5x²)^3-(2)^3=(5x²-2)((5x²)²+5x²*2+2²)

Answer 2

Answer:

$(5x^2-2)(25x^4 +10x^2+4)$

Step-by-step explanation:

125x^6 – 8

We write the numbers in exponential form

125= 5*5*5 = 5^3

8 = 2*2*2= 2^3

Now 125x^6 - 8 becomes 5^3x^6 - 3^3

5^3x^2*3- 3^3

$(5x^2)^3 - 2^3$

We got the expression in cube form a^3- b^3= (a-b)(a^2+ab+b^2)

$(5x^2)^3 - 2^3$

a= 5x^2  and b= 2

$(5x^2)^3 - 2^3=(5x^2-2)((5x^2)^2- 5x^2 * 2+ 2^2)$

=$(5x^2-2)(25x^4 +10x^2+4)$