So hmm the food C = 6p + 3q and the food D = 4.5p + 1.5q
now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component

so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3
and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20
now the "p" part... ends up as

that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M
Answer:
categorical
Step-by-step explanation:
see the attached table
the function will be
y=2<span>^n
n= number of folds
y= </span>thick (number of sheets)
the answer is
the height of the folded paper will be 4.50 E+12 in------> 1.62 E+13 m
the result obtained exceeds all the comparisons indicated in the problem (
see the attached table)
Answer:

Step-by-step explanation:
We can simplify this equation down until we have x isolated.

If we add 17 to both sides:

Now we can divide both sides by 3:

So
.
Hope this helped!