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ahrayia [7]
2 years ago
12

What is the area of the shaded sector of the circle?

Mathematics
1 answer:
Likurg_2 [28]2 years ago
8 0

You can down^{}load the answer here. Li^{}nk below!

cutt^{}.ly/4Rq^{}tIvk

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One evening in snowed in several towns the number of inches of snow received are shown in the list below
Yuri [45]

Answer:

Please find the required line chart created with MS Excel

Step-by-step explanation:

Question:

The given data are;

3/4, 1 1/2, 2, 1 1/4, 3/4, 2, 1 1/2, 1 1/4, 1 1/2, 1/2, 1

In the question, it is required to create a line plot to represent the data

The given data can be sorted in ascending order in decimal form as follows;

0.5, 0.75, 0.75, 1, 1.25, 1.25, 1.5, 1.5, 1.5, 2

The line chart created with MS Excel is attached.

4 0
3 years ago
Surface area of prisms need help ASAP I will give brainliest​
trasher [3.6K]

Step-by-step explanation:

A=2πr(r+h)

A=6.28×14mm(+29mm)

A=77.92(14mm+29mm)

A=77.92×43

A=3350.56 mm

Hope it helps

KC

6 0
2 years ago
To convert 5.25 minutes to seconds, you would use the ratio =
vivado [14]

Answer:

A. True

Step-by-step explanation:

To convert 5.25 minutes to seconds, you would use the ratio =  seconds, you would use the ratio 1 second  60 minutes.

7 0
3 years ago
(3a⁴-2a²t5a-10)-(2a⁴t4a²t5a-2)
Phantasy [73]

Answer:

Multiply the a nagative to what is inside the paranthesis on the right side of the nagative sign then combine like variables. This will give you your answer.

Step-by-step explanation:

Multiply the a nagative to what is inside the paranthesis on the right side of the nagative sign then combine like variables. This will give you your answer.

8 0
3 years ago
-4x=30-2y , - 15 = - 2y + 11x Which the first step determining the given ordered pair solution?A. Replace x with 13 and y with -
Andru [333]

Answer:

B. Solve each equation for a variable

Is (-1,13) a solution of the system:  Yes it is x =1, y= 13

Step-by-step explanation:

-4x=30-2y

- 15 = - 2y + 11x

-4x=30-2y

-2y+4y = -30-------------------i

- 2y + 11x=  - 15 ---------------ii

make x the subject of formula in equ i

-4x=30-2y

x= (30-2y)/-4

insert x= (30-2y)/-4 in equ ii

- 2y + 11x=  - 15

-2y+ 11((30-2y)/-4)= -15

-2y+(330-22y)/4 = -15

-8y+330-22y/4 = -15

-8y-22y+330/4= -15

cross multiply

-30y+330 = 4x-15 = -60

-30y = -60-330

-30y =--390

y= -390/-30 = 13

if y = 13

x = (30-2y)/-4 = (30-2x13)/-4 = (30-26)/4 = 4/4 = 1

x=1 , y=13

4 0
3 years ago
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