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Alik [6]
3 years ago
7

A bakery used 25% more butter than last month. If the bakery used 240 kilograms of butter last month, how much did it use this m

onth?
Mathematics
1 answer:
denpristay [2]3 years ago
5 0

Answer:

Sorry no Inglés plis spanich :/

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Graham paid $87.45 for a pair of jeans. This amount included a tax of 40%. What was the cost of the jeans before tax?
kiruha [24]

The final price is the cost plus the tax.

Since we know the tax and a percent, we can write this as

T = C(1+r)

T = what Graham paid = $87.45

C = cost before tax

r = tax rate expressed as a decimal = .40

Plugging in what we know

87.45 = C (1+.4)

87.45 = C(1.4)

Divide both sides by 1.4

C = $62.46

5 0
3 years ago
Steve built a square dog pen that has a perimeter of 240 inches.
Trava [24]
Perimeter of square = 4 x l

so ATC 4 x l = 240
= 240/40= l
so 60 = l

the answer is 60 inches.
6 0
3 years ago
A group of high school athletes has an average GPA of 2.7 with a standard deviation of 0.9. a)Find the percentage of athletes wh
mart [117]

Answer:

a) The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is 3.645.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.7, \sigma = 0.9

a)Find the percentage of athletes whose GPA more than 1.665.

This is 1 subtracted by the pvalue of Z when X = 1.665. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.665 - 2.7}{0.9}

Z = -1.15

Z = -1.15 has a pvalue of 0.1251

1 - 0.1251 = 0.8749

The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.

His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.

Z = \frac{X - \mu}{\sigma}

1.05 = \frac{X - 2.7}{0.9}

X - 2.7 = 1.05*0.9

X = 3.645

John's GPA is 3.645.

8 0
3 years ago
1/10( x + 130) = -2(3-X)<br><br> I need help
Artist 52 [7]

Answer:

x = 10

Step-by-step explanation:

1/10(x + 130) = -2(3 - x)

x + 130 = -20(3-x)

x + 130 = -60 + 20x

x - 20x = -60 - 130

-19x = -190

x = 10

5 0
3 years ago
Please need some help with arithmetic functions!!!
frutty [35]
A, perhaps,plz check the definition of functions
8 0
3 years ago
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