1/10( x + 130) = -2(3-X) I need help

Simplify the expression below as much as possible. (8 + 5i) + (10 +6i) - (3 +61)

yarga [219]

Answer is -46+11i
Because

Remove unnecessary parenthese
Then

When there is a in front of an expression in parentheses, the expression remains the same

Then

Add the numbers

Calculate the sum or difference

Collect like terms

6 0

3 years ago

How many acute, obtuse, and right angles are in this figure?

Tanya [424]

Hey!

I hope you don't mind, but before I answer this question I'd like to do a quick review of some general angles and how to tell which is which.

QUICK REVIEW

So, let's first review what an acute angle is. An acute angle is an angle that is smaller than 90°. The word acute basically means having a sharp or pointy end. So this is a helpful way to remember what an acute angle is.

Now, let's review what an obtuse angle is. An obtuse angle is an angle that is more than 90°. If an angle measures over 90° that it is more than likely that it is an obtuse angle.

Last but not least a right angle. A right angle is an angle that has to be exactly 90°. If an angle is 90° than it is most definitely a right

END QUICK REVIEW

Let's start by finding out the angle in the top left hand corner. The angle is clearly no more that 90° and is not 90° exactly. This angle must be an acute angle. We can also tell that it is an acute angle because the angle is sharp.

Now let's look at the angle on the bottom left hand corner. The angle is clearly no less than 90° and more than 90° exactly. This angle must be an obtuse angle.

Since the angles are basically the same on the other side, we won't be reviewing those. Now we'll count all the angles we have.

Acute Angles - 2

Obtuse Angles - 2

Right Angles - 0

So, this means that in the figure shown above, there are 2 acute angles, 2 obtuse angles, and no right angles.

Hope this helps!

- Lindsey Frazier ♥

4 0

2 years ago

What is the length of the hypotenuse of a right triangle with sides that measure 7 cm and 24 cm?

Paul [167]

The length of the hypotenuse of a right triangle with sides that measure 7 cm and 24 cm is 25 cm

Solution:

Given a right angled triangle,

The sides measure 7 cm and 24 cm

We have to find the length of hypotenuse

For a right angled triangle, by Pythagorean theorem, which states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

From above definition we get,

$c^2 = a^2 + b^2$

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

"b" is the length of other side of triangle

Here, a = 7 and b = 24 and c = ?

$c^2 = 7^2 + 24^2\\\\c^2 = 49 + 576 = 625$

Taking square root on both sides,

$c = \sqrt{625}\\\\c = 25$

Hence the length of hypotenuse is 25 cm

7 0

3 years ago

Can someone please explain how to solve this problem(31)

pogonyaev

Answer:

(-1.92, 1.08)

Step-by-step explanation:

The incenter is the center of the largest circle that can be inscribed in the triangle. That circle is called the incircle. The incenter is at the point of intersection of the angle bisectors. For a right triangle, the inradius (the radius of the incircle), is found from a simple formula:

r = (a + b - c)/2 . . . . . where c is the hypotenuse, and a and b are the legs

In your triangle, the inradius is ...

r = (5 + 3 -√(5² +3²))/2 = 4 -√8.5 ≈ 1.08452

Among other things, this means the coordinates of the incenter are about (1.08, 1.08) from the right angle vertex, so are about ...

incenter ≈ (-1.92, 1.08)

4 0

3 years ago

A silo is not the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cu

Gnom [1K]

Answer:

$7803.72

Step-by-step explanation:

We have been given that a silo is in the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cubic meter. We are asked to find the total cost to fill the silo with soybeans.

First of all, we will find the volume of silo using volume of cone formula.

$\text{Volume of cone}=\frac{1}{3}\pi r^2 h$ , where,