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Dvinal [7]
4 years ago
8

What is the multiplicative inverse of 1/2

Mathematics
1 answer:
iragen [17]4 years ago
6 0
The numerator of the multiplicative inverse is 2 and the denominator is 3. All the examples in Reciprocal<span> demonstrate that a number multiplied by its inverse gives a product of 1.</span>
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Expressions, equations, &amp; inequalities
dem82 [27]

Answer:

The number of sandwiches sold is 73. This is because it is multiplied by the expression for the money received per sandwich.

The cost to make each sandwich is <em>S. </em>This is stated in the first sentence of the problem.

<em />

The profit is 0.2<em>S. </em>This is because they sell each sandwich for an additional 20% of the cost ( S )

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The amount of money the band receives is (<em>S </em>+ 0.2<em>S </em>). This is because it is the price per sandwich.

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3 0
2 years ago
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A particle moves with velocity function v(t) = 2t^2 - 3t - 3, with v measured in feet per second and t measured in seconds. Find
SashulF [63]
V(t) = 2t^2 - 3t - 3

for an acceleration a(t),
a(t) = d (v(t)) / d t
a(t) = 4t - 3

at t=2
a(2) = 8 - 3
a(2) = 5 feet/s^2

3 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
3 years ago
Please show work and solve will mark as brainly
dolphi86 [110]

Answer:

4 hours

Step-by-step explanation:

63-35=28 28 divided by 7= 4

8 0
3 years ago
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Which pair of numbers is relatively prime? A. 5 and 75 B. 12 and 51 C. 7 and 20 D. 15 and 21
Zielflug [23.3K]

The only number not divisible by anything except itself and 1, was C. 7

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3 years ago
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