Answer:
A
Explanation:
In my opinion, it is best he works the extra $1300 which wouldn't require him to abandon his college plans, wait an extra year or get himself into the trouble of loans.
Cheers
Depends, but I'd say false.
Using the knowledge in computational language in C++ it is possible to write a code that Find the Average of the sum of prime numbers between 1 to any given number
<h3>Writting in C++ code:</h3>
<em />
<em>#include <iostream></em>
<em>using namespace std;</em>
<em>bool isPrime(int n){</em>
<em> for(int i = 2; i < n/2; i++){</em>
<em> if(n%i == 0){</em>
<em> return false;</em>
<em> }</em>
<em> }</em>
<em> return true;</em>
<em>}</em>
<em>int findPrimeSum(int n){</em>
<em> int sumVal = 0;</em>
<em> for(float i = 2; i <= n; i++){</em>
<em> if(isPrime(i))</em>
<em> sumVal += i;</em>
<em> }</em>
<em> return sumVal;</em>
<em>}</em>
<em>int main(){</em>
<em> int n = 15;</em>
<em> cout<<"The sum of prime number between 1 to "<<n<<" is "<<findPrimeSum(n);</em>
<em> return 0;</em>
<em>}</em>
See more about C++ code at brainly.com/question/19705654
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Answer:
- with(open("numbers.txt")) as file:
- data = file.readlines()
- runsum = 0
- largest = 0
-
- for x in data:
- if(int(x) > largest):
- largest = int(x)
- runsum += largest
-
- print(runsum)
Explanation:
The solution code is written in Python 3.
Firstly, open a filestream for numbers.txt (Line 1) and then use readlines method to get every row of data from the text files (Line 2).
Create a variable runsum to hold the running sum of number bigger than the maximum value read up to that iteration in a for loop (Line 3).
Use a for loop to traverse through the read data and then check if the current row of integer is bigger than the maximum value up to that point, set the current integer to largest variable and then add the largest to runsum (Line 6 - 9).
At last display the runsum to console terminal (Line 11).