Explanation:
Therefore, an entrepreneur is an organization builder. 6. Gap-filling function – The gap between human needs and the available products
Answer:
10G Ethernet
Explanation:
These are the options for the question;
A) 10BASE Ethernet
B) Gigabit Ethernet
C) Fast Ethernet
D) 10G Ethernet
From the question, we are informed about instance of my company deciding to upgrade the older office Ethernet network and needs the fastest speed possible but has decided against fiber optic cable. In this case my solution for this problem is getting
10G Ethernet. Ethernet can be regarded as traditional technology that connects devices in LAN(wired local area network) as well as WAN(wide area network) which allows them to have communication with each other through a protocol, this protocol is reffered to as common network language, it also be regarded as rules. 10 Gigabit Ethernet which is a technology ofgroup of computer networking that enables transmission of Ethernet frames at high rate of 10 gigabits per second. Therefore, 10G Ethernet is the solution since we need
the fastest possible speed.
Answer:
A good Universal serial bus i use is a San Disk
Explanation:
others are a WD easystore, A samsung MUF-BA.... etc
Answer:
<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>
tuition = 10000
rate = 0.04
for i in range(1,15):
tuition = tuition + tuition * rate
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Explanation:
<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>
tuition = 10000
rate = 0.04
<em>The next line iterates from year 1 to year 14</em>
for i in range(1,15):
<em>This line calculates the tuition for each year</em>
tuition = tuition + tuition * rate
<em>The next 3 lines prints the tuition for year 1 to year 10</em>
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Ccleaner for Android can be set to automatically run on schedule. But please check have u update it.
<span />