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3 years ago

Predict the total pressure in Container C if the initial pressure in

Chemistry

1 answer:

finlep [7]3 years ago

6 0

Answer:

$98 \times x6x \geqslant {36461 { {3 \frac{ \sqrt[ |?| ]{?} }{?} }^{2} }^{?} }^{2}$

okay

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Convert the following into balanced equations:

masya89 [10]

Balanced equation :

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

Organic Nomenclature:

Hexane is a six-carbon straight-chain alkane. The prefix "hex-" signifies the number 6 for alkanes, and the suffix "-ane" is what clarifies that this hydrocarbon has only carbon-carbon single bonds. There are no double or triple bonds.

Elaborating the equation :

The mass of hexane available for this reaction is converted to a quantity of moles by multiplying by its density to get a mass and then dividing by its molar mass. This quantity of moles is then related to the quantity of moles of oxygen by their molar ratios. According to this balanced reaction equation, every 2 moles of hexane burned will require the reaction of 19 moles of oxygen gas.

Learn more about balanced equation :

brainly.com/question/20780772

#SPJ4

5 0

2 years ago

Dissolve 30 g of sodium sulphate into 300 mL of water

Aneli [31]

Answer:

number of moles = 0.21120811

Explanation:

To find the number of moles, given the mass of the solute, we use the formula:

$\mathrm{n = \dfrac{ m }{ M } }$

$\mathrm{n = number\:of\:moles\:(mol)}$

$\mathrm{m = mass\:of\:solute\:(g)}$

$\mathrm{M = molar\:mass\:of\:solute\:( \dfrac{ g }{ mol } )}$

Label the variables with the numbers in the problem:

$\mathrm{n =\:?}$

$\mathrm{m =30\:g }$

$\mathrm{M =\:?\:Calculate\:the\:molar\:mass }$

The first thing we have to do is find the molar mass of sodium sulfate, in order for us to use the formula for finding the number of moles:

Formula for finding the molar mass of sodium sulfate:

$M({ \left Na \right }_{ 2 } { \left So \right }_{ 4 }) = m \left( Na \right) +m \left( S \right) +m \left( O \right)$

For the variables and what they mean are below for finding the molar mass of sodium sulfate:

$\mathrm{M =molar\:mass }$

$\mathrm{m =moles=2\:moles\:for\:Na\:,1\:mole\:for\:S,\:and\:4\:moles\:for\:O}$

$\mathrm{Na =sodium=22.99\:g }$

$\mathrm{S =sulfur=32.06\:g }$

$\mathrm{O =oxygen=16.00\:g }$

Plug the numbers into the formula, to find the molar mass of sodium sulfate:

$M({ \left Na \right }_{ 2 } { \left So \right }_{ 4 }) = m \left( Na \right) +m \left( S \right) +m \left( O \right)$

$\mathrm{Substitute\:the\:values\:into\:the\:formula}$

$M = 2 \left( 22.99 \right) +1 \left( 32.06 \right) +4 \left( 16.00 \right)$

$\mathrm{Multiply\:2\:by\:22.99\:to\:get\:45.98\:and\:1\:by\:32.06\:to\:get\:32.06}$

$\mathrm{M = 45.98+32.06+4\:(16)}$

$\mathrm{Multiply\:4\:by\:16\:to\:get\:64}$

$\mathrm{M = 45.98+32.06+64}$

$\mathrm{Add\:45.98\:and\:32.06\:to\:get\:78.04}$

$\mathrm{M = 78.04+64}$

$\mathrm{Add\:78.04\:and\:64\:to\:get\:142.04}$

$\mathrm{M = 142.04}$

Now that we have found the molar mass, we can calculate the number of moles in the solution of sodium sulfate with the formula:

$\mathrm{n = \dfrac{ m }{ M } }$

$\mathrm{n =\:?}$

$\mathrm{m =30\:g }$

$\mathrm{M = 142.04\:g/mol}$

$\mathrm{Substitute\:the\:values\:into\:the\:formula}$

$\mathrm{n = \dfrac{ 30 }{ 142.04 }}$

$\mathrm{Divide\:142.04\:by\:30\:to\:get\:0.21120811}$

$\mathrm{n = 0.21120811}$

0.21120811 rounded gives you 0.2112

or if you did the problem without decimals

30 grams of sodium sulfate divided by its molecular weight – which we found to be 142 – gives us a value of 0.2113 moles.

3 0

2 years ago

Lucy learns that the lymphatic system is part of the circulatory system. She wants to learn more about it and reads more careful

adoni [48]

Answer: C because I’m smart

Explanation:

3 0

3 years ago

When balance the following chemical equations N2+O2= NO2 the coefficient for O2 is

Papessa [141]

Answer:

Explanation:

N₂ + O₂ ---> NO₂

balance

N₂ + 2O₂ ---> 2NO₂

4 0

3 years ago

Ap LSCHpnGKIASAJQSMZc4qoidborFmvFig/USHTVPBWHqozowvg Viewo

Shalnov [3]

Answer:

Balance and Unbalanced.

4 0

3 years ago