three carbon is the most reactive
The ending carbon atoms of an extended aliphatic chain can combine in organic chemistry to create a closed system or ring, which results in cycloalkanes. These substances are referred to as cyclic substances. Cyclopropane, cyclobutane, cyclopentane, among many more, are examples.
Since cyclopropane has rings in its structural arrangement, it is less stable than the other cycloalkanes mentioned above. The positional orientation of the atoms of cycloalkane compounds, which have a tendency to emit a very high and unfavorable energy, is known as the ring strain. The ring becomes unstable and reactive due to the release of heat energy that has been trapped in its bonds and molecules.
The smaller cycloalkanes are more significantly impacted by the ring strain in terms of their structural makeup and conformational behavior.
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Answer:
As we are not provided with ¹H-NMR spectrum therefore we can not conclude a single result for the minor chlorination of propane with Molecular formula C₃H₆Cl₂.
Hence, we will draw all the possible isomers with molecular formula C₃H₆Cl₂ and predict the ¹H-NMR spectrum for each of them separately.
Below is the structures of possible minor products and the NMR spectrum respectively.
Possible Product A:
If the minor product formed is 2,2-Dichloropropane then it will give only one singlet peak in NMR spectrum.
Possible Product B:
If the minor product is 1,1-Dichloropropane then it will exhibit two triplets and one multiplet as shown in figure.
Possible Product C:
If the minor product is 1,2-Dichloropropane then it will give four peaks in NMR. The extra peak is formed due to two enantiomers about the chiral carbon.
Possible Product D:
If the minor product is 1,3-Dichloropropane then it will exhibit one triplet and one quintet signal as shown in figure.
Answer is periodic because only happens in certain times
Answer:
im not a brain wiz but i think 20
Explanation: