Igneous rocks metamorphic rocks and sedimentary rocks
Answer:
The density of liquid is 3 g/mL.
The mass of liquid is 60 g.
The volume of liquid is 10 mL.
Explanation:
Given data:
Density of liquid = ?
Mass of liquid = 30 g
Volume of liquid = 10 mL
Solution:
d = m/v
d = density
m = mass
v = volume
Now we will put the values in formula.
d = 30 g/ 10 mL
d = 3 g/mL
The density of liquid is 3 g/mL.
2nd:
Given data:
Density of liquid = 2 g/mL
Volume of liquid = 30 mL
Mass of liquid = ?
Solution:
d = m/v
2 g/mL = m/ 30 mL
m = 2 g/mL×30 mL
m = 60 g
The mass of liquid is 60 g.
3rd:
Given data:
Density of liquid = 5 g/mL
Mass of liquid = 50 g
Volume of liquid = ?
Solution:
d = m/v
5 g/mL = 50 g/ v
v = 50 g/5 g/mL
v = 10 mL
The volume of liquid is 10 mL.
Answer:
37.3g
Explanation:
Formula of the compound:
FeCl₃
Number of chloride ions = 4.13 x 10²³ ions
First find the number of moles in this ions;
6.02 x 10²³ ions are contained in 1 mole of a substance
4.13 x 10²³ ions contains 
= 0.69mole chloride ions
Now;
3 mole of chloride ions are contained in 1 mole of FeCl₃
0.69 mole of chloride ions will contain 
= 0.23mole of FeCl₃
To find the mass;
Mass of FeCl₃ = number of moles x molar mass
molar mass of FeCl₃ = 55.8 + 3(35.5) = 162.3g/mol
Mass of FeCl₃ = 0.23 x 162.3 = 37.3g
The pH of the solution at equivalence point is dependent on the strength of the acid and strength of the base used in the titration.
For strong acid-strong base titration, pH = 7 at equivalence point
For weak acid-strong base titration, pH > 7 at equivalence point
For strong acid-weak base titration, pH < 7 at equivalence point
https://www.khanacademy.org/test-prep/mcat/chemical-processes/titrations-and-solubility-equilibria/a...
The indicator changes color when the pH changes at the endpoint of the titration. So, you need to determine what is present at the point and find the pH at the point. Then, you can reference a table of indicators to choose one whose color will change over the pH that includes your equivalency point.
