Answer:
5√3 ft/s
Step-by-step explanation:
Let h represent the horizontal distance of the kite from the person. Let s represent the string length. Then the Pythagorean theorem tells us ...
s^2 = 100^2 + h^2
2s·ds/dt = 0 + 2h·dh/dt
ds/dt = (h/s)·dh/dt
So, we need to know the horizontal distance when s=200.
200^2 = 100^2 + h^2
40000 -10000 = h^2
h = 100√3
Substituting known values into the equation for ds/dt, we have ...
ds/dt = (100√3)/(200)(10 ft/s) = 5√3 ft/s
The string must be let out at 5√3 ft/s when it is already 200 ft long.
Answer:
a. 32,2°C
b. 131 °F
c. -28,9°C
Step-by-step explanation:
We must consider the following formula:
(x-32) × 5/9 = y , where x= temperature in °F an y= temperature in °C
Then,
a) In the formula we replace x=90° F, and we have: y = (90-32)× 5/9 = 32,2 °C
b) In the formula we replace y=55° C, and we have: 55 = (x-32)× 5/9 ⇒ 55×9/5 =x-32 ⇒ x=(55×9/5)+32 = 131 °F
c) In the formula we replace y= -20° C and we have: -20 = (x-32)× 5/9 = -4°F
D
L
K
C
Answers in order from 5-8
20% as a decimal is 0.2
Hope this helps!
