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liubo4ka [24]
3 years ago
12

Write the sentence as an inequality. thirteen is at least the difference of a number v and 1.

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0

Answer:

v - 1 ≥ 13.

Step-by-step explanation:

'is at least' is written as ≥ ( greater or equal to).

v - 1 ≥ 13.

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Given: f(x) = 2x + 5 and g(x) = x2 and h(x) = -2x<br><br> h(g(f(x)))
alexgriva [62]
Hello here is a solution :
<span>h(g(f(x))) ?

</span>g(f(x))= g(2x+5)=(2x+5)²=(2x)²+2(2x)(5)+5² = 4x²+20x+25
h(g(f(x)))(x) = h(4x²+20x+25) = -2(4x²+20x+25) 
h(g(f(x)))(x) = -8x²-40x-50
8 0
2 years ago
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You put $500 in the bank for 2 years with a 3.2% interest rate. How much Interest is earned?
kvv77 [185]

Answer:1.0%

Step-by-step explanation:

hopes it help

5 0
2 years ago
The vertex of this parabola is at (-1,-3) which of the following could be its equation
Gnesinka [82]
Since these are parabolas with y being squared, the standard form of such a parabola with vertex at (h, k) is 

<span>x = a(y - k)^2 + h </span>

<span>There are no steps. Just look at what is inside the parentheses and compare it to (y - k) with k = -3. </span>
<span>Then look at what is added and compare it to h = -1. </span>

<span>For instance, A has (y + 1) in parentheses. So k = -1. And it has -3 added, so h = -3. That would be a vertex at (-3, -1).</span>
6 0
3 years ago
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What is the result when 9r^3 + 27x^2 + 11x +1 is divided by 3x + 1?​
morpeh [17]

Answer:

the answer is 3x^2 + 8x + 1

Step-by-step explanation:

(I used x as the variable due to the invalid difference of variables in your question )

To find the correct answer, I had to use polynomial division.

(9 x 3 + 27 x 2 + 11 x + 1) / (3 x + 1)

= ( 3 x + 1 ) ( 3 x 2 + 8 x + 1 ) / (3 x + 1)

= 3 x 2 + 8 x + 1

6 0
2 years ago
Can you help me with these two questions please !!!!
zubka84 [21]

Answer: (x+2)^{2}+(y-4)^{2} =16

and

(x-6)^{2} +(y+4)^{2} =20

Step-by-step explanation:

Equation for a Circle

(x-h)^{2} +(y-k)^{2} =r^{2}

h= -2 k= 4 r= 4

(x+2)^{2}+(y-4)^{2} =16

Part 2

Complete the Square

x^{2} +y^{2} -12x+8y+32=0\\(x^{2}-12x+-)+(y^{2}+8y)=-32\\(x^{2} -12x+36)=(y^{2} +8y+16)=-32+36+16\\\\(x-6)^{2} +(y+4)^{2} =20

6 0
3 years ago
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